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Question: Ninety-Six Percent Of A Solute Is Removed From 100 ML Of An Aqueous Solution By Extraction With Two 50-ML Portion Of An Organic…

Here is our question: 4. Ninety-six percent of a solute is removed from 100 mL of an aqueous solution by extraction with two 50-mL portion of an organic solvent. What is the distribution ratio of the solute?

Hint: Let the original amount be 100, Let % extract in a single step = x

(a) Total extracted = amount extracted from 1^st extraction + amount extracted from 2^nd extraction 96% (100) = x% (100 ) + x % ( ?)

96 = x +x% (?) a diagram might help.

(b) Which equation related % extracted with D?

Once x is solved, D can be found from the proper equation

Answer

Apply the following theory to do:

Here is our answer:

After we have established the above formula, we continue to substitute numbers and solve the equation to find x

Now, to calculate the answer to question b is very easy, like this:

Relevant knowledge

Note when solving the exercise to calculate the percentage concentration of the solution
– It is necessary to read the problem carefully to fully determine the given components and the components that need to be calculated
– Remember the formulas to apply correctly
– Calculate carefully to get the best results, avoid having to do it again and again.
You can solve problems on calculating percentages by following these basic steps:
– Read the problem carefully to determine the number of substances in the solution, especially the residues of the reactants.
– Calculate the mass of the solution after taking part in the reaction according to the formula:
m(solution) = mass of solutes added to solution + mass of solution – mass of precipitate – mass of gas.
– Calculate the mass of solute present in the solution to determine the percentage concentration.
– Calculate the percentage concentration according to the given formula.

Conclusion

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