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*Today we are going to come up with new task, that is about ”A metal bar is in the xy-plane with one end of the bar at the origin….“. We have found the solution to this question, along with interesting information related to it, thanks to its novelty and interest. This will help you to develop a more research-oriented mindset, and make it easier for you to answer these types of questions. This is where we will focus to gain this useful and new knowledge!*

## Question: “A metal bar is in the xy-plane with one end of the bar at the origin….”

A metal bar is in the xy-plane with one end of the bar at the origin. A force F =( 6.22 N )i^+( -2.81 N )j^ is applied to the bar at the point x= 3.58 m , y= 3.46 m.

* Part A*: What is the position vector r for the point where the force is applied? Enter the x and y components of the radius vector separated by a comma.

* Part B*: What are the magnitude of the torque with respect to the origin produced by F?

** Part C**: What are direction of the torque with respect to the origin produced by F?

## Answer: “A metal bar is in the xy-plane with one end of the bar at the origin….”

* Part A*:

r_{x}= 3.58m

r_{y} = 3.46 m

** Part B**:

Torque, T = r x F, i.e cross product of r and F.

T = (3.58i + 3.46j + 0k) x (6.22i+(-2.81j) + 0k) = 0i + 0j – 31.58k

Hence, magnitude of torque is sqrt(0+ 0+ (31.58)^{2}) = 31.58N

* Part C*:

Direction of Torque is -z direction.

## Relevant knowledge

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## Conclusion

*This is how you solve this type of task “A metal bar is in the xy-plane with one end of the bar at the origin….”. Please leave a message below if you have any questions or comments.*

*Thanks for reading!!!*

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