Today we are going to come up with new task, that is about ”A uniform beam of length l and mass m has its lower end pivoted at p on the floor“. We have found the solution to this question, along with interesting information related to it, thanks to its novelty and interest.  This is where we will focus to gain this useful and new knowledge!

Question: “A uniform beam of length l and mass m has its lower end pivoted at p on the floor”

Answer: “A uniform beam of length l and mass m has its lower end pivoted at p on the floor”

Given Data

• The mass of the uniform beam is:  .

• The length of the uniform beam is: $L=15m$.

• The angle of inclination of the beam with the horizontal is: $\theta ={22}^{\circ }$.

• The mass of the box is: $M$ .

• The point where this box is attached , when measured from top end is: $\frac{\mathrm{L/4.}}{}$

a.   

b. 

c. 

d. 

Relevant knowledge

When a force is applied at a distance, it will be eccentric to apply torque. The torque required to produce the same amount will be lower the more eccentric the force. You can think of it as:

Here, $F$ is the applied force and  is the eccentric distance.

Conclusion

This is how you solve this type of task “A uniform beam of length l and mass m has its lower end pivoted at p on the floor”. Please leave a message below if you have any questions or comments.

Thanks for reading!!!