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Questions: For the circuit shown in the figure(Figure 1) find the current through each resistor.

(A) For the circuit shown in the figure(Figure 1) find the current through each resistor.

Express your answers using two significant figures. Enter your answers numerically separated by commas.

(B) For the circuit shown in the figure find the potential difference across each resistor.

Express your answers using two significant figures. Enter your answers numerically separated by commas.

Answer

a) Req= 6ohm

So net current =24/6 =4 A

So

• Current through 2 ohm = 4A (ans)
• Current through 4 ohm = 2A (ans)
• Current through 6 ohm = 4/3A =1.33 A (ans)
• Current through 12 ohm = 2/3A =0.67 A (ans)
• Current through 8 ohm = 2 A (ans)

b)

• Voltage through 2 ohm = 4A *2 =8 V (ans)
• voltage through 4 ohm = 2A*4 =8 V (ans)
• voltage through 6 ohm = 6*4/3 =8 V (ans)
• voltage through 12 ohm = 2/3A*12 =8 V (ans)
• voltage through 8 ohm = 2A*8 =16 V (ans)

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Series and parallel combination of resistors:

In an electric circuit, resistors can be connected in series or parallel. A series combination of resistors will allow the same current to pass through each resistor, but the potential difference between each resistor is different. This is the equivalent resistance of resistors that are connected in series.

R_eq = R₁ + R₂ + R₃ + ……. (where; R₁,R₂, R₃……. are the resistance of the individual resistors)

Parallel combination of resistors means that the potential difference across each resistor remains the same, but the current flowing through each resistor differs. You can find the equivalent resistance for parallel combinations of resistors by:

• If you have one voltage source or multiple voltage sources in the branch, and several series-parallel resistances, the Equivalent resistance method can be used to simplify the circuit and create a single voltage supply and equivalent resistance.
• The equivalent resistance is the resistance value that can be connected to the voltage source separately and provide the same source current as the original circuit.
• The Method of Equivalent Resistance is a complement to Ohm’s Law, which we use for computing the source current in the simplified circuit.

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