Home/dhtutoria/Best Answers
  1. Asked: May 12, 2022In:

    Fixing the error: no value accessor for form control with name

    dhtutoria Expert
    This answer was edited.

    The cause: The error happens because of adding the formControlName to the label and not the input. The solution:  You have this: <div > <div class="input-field col s12"> <input id="email" type="email"> <label class="center-align" for="email" formControlName="email">Email</Read more

    The cause: The error happens because of adding the formControlName to the label and not the input.

    The solution:  You have this:

    <div >
  <div class="input-field col s12">
    <input id="email" type="email">
    <label class="center-align" for="email" formControlName="email">Email</label>
  </div>
</div>
    Change it to :
    <div >
  <div class="input-field col s12">
    <input id="email" type="email" formControlName="email">
    <label class="center-align" for="email">Email</label>
  </div>
</div>
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    • 7
  2. Asked: May 12, 2022In:

    Solving the error: c++ incomplete type is not allowed

    dhtutoria Expert

    The cause: The issue happens when compiler finds identifier which is one of the recognized data type nevertheless its definition is not clear at all. Solution: Put your definitions as the following direction in order to compile the code: Modified code: class Ball; class Player { public: void doSometRead more

    The cause:

    The issue happens when compiler finds identifier which is one of the recognized data type nevertheless its definition is not clear at all.

    Solution: Put your definitions as the following direction in order to compile the code:

    Modified code:

    class Ball;
 class Player { 
public: 
void doSomething(Ball& ball); 
private: 
}; 

class Ball { public: 
Player& PlayerB; 
float ballPosX = 800; 
private: 

}; void Player::doSomething(Ball& ball) {
 ball.ballPosX += 10; // incomplete type error occurs here. 
} 
int main() 
{ 
}
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    • 15
  3. Asked: May 12, 2022In:

    The best way to fix the avrdude: stk500v2_receivemessage(): timeout error

    dhtutoria Expert

    The cause: Because the board is not suitable with your device, or it works instability Solution: To solve the issue, click in turn order: tools/boards/Boards Manager and continue to choose "updatable" in the segment (Type).  Afterward, compress update button on the right side of each item which youRead more

    The cause: Because the board is not suitable with your device, or it works instability

    Solution:

    To solve the issue, click in turn order: tools/boards/Boards Manager and continue to choose “updatable” in the segment (Type).  Afterward, compress update button on the right side of each item which you select.

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    • 7
  4. Asked: May 12, 2022In:

    Resolved the problem of the throw new typeerror(‘router.use() requires a middleware function but got a ‘ + gettype(fn));

    dhtutoria Expert
    This answer was edited.

    The cause: This error is caused by the fact that you are lacking the router exports module. Solution: Incase of using express above 2.x, you can do like that:  change the code app.use('/', routes); into app.use(app.router); routes.initialize(app);

    The cause: This error is caused by the fact that you are lacking the router exports module.

    Solution: Incase of using express above 2.x, you can do like that:

     change the code

    app.use('/', routes);

    into

    app.use(app.router);
routes.initialize(app);
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    • 10
  5. Asked: May 12, 2022In:

    Fixing the error: swift type of expression is ambiguous without more context

    dhtutoria Expert
    This answer was edited.

    The cause: The reason is that you you changed the name of a Variable and did not refactor when doing that. Solution: It will work if you declare clearly the inputs and then mapping task do the following way:  Replace the real class of "$0" for "WhateverClass" in that code snippet. Fixed code:  let iRead more

    The cause: The reason is that you you changed the name of a Variable and did not refactor when doing that. Solution: It will work if you declare clearly the inputs and then mapping task do the following way: 

    Replace the real class of “$0” for “WhateverClass” in that code snippet. Fixed code: 

    let imageToDeleteParameters = imagesToDelete.map { (whatever : WhateverClass) -> Dictionary<String, Any> in ["id": whatever.id, "url": whatever.url.absoluteString, "_destroy": true] }
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    • 12
  6. Asked: May 12, 2022In:

    Stabilizing the error with the best answers: typeerror: ‘series’ objects are mutable, thus they cannot be hashed

    dhtutoria Expert
    This answer was edited.

    The cause: gene_name = no_headers.iloc[1:,[1]] This error happens because you passed a list of columns (single, but still a list). When you later do this: gene_name[x] Now you have a Series object with a single value, so can't hash the Series. Solution: You can resolve the error by creating Series fRead more

    The cause:

    gene_name = no_headers.iloc[1:,[1]]

    This error happens because you passed a list of columns (single, but still a list). When you later do this:

    gene_name[x]

    Now you have a Series object with a single value, so can’t hash the Series.

    Solution: You can resolve the error by creating Series from the start.

    gene_type = no_headers.iloc[1:,0]
gene_name = no_headers.iloc[1:,1]
disease_name = no_headers.iloc[1:,2]
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    • 16
  7. Asked: May 12, 2022In:

    Quick handling of the Connect is not a valid member of TextButton error

    dhtutoria Expert
    This answer was edited.

    The cause: This error happens because you have to connect to an event on the TextButton, not the button itself. Solution:  I suggest the Activated event as it fires when someone clicks on the button, and it also works on mobile. for g, n in pairs(PlayersList:GetChildren()) do local ind = n. Text locRead more

    The cause: This error happens because you have to connect to an event on the TextButton, not the button itself.

    Solution:  I suggest the Activated event as it fires when someone clicks on the button, and it also works on mobile.

    for g, n in pairs(PlayersList:GetChildren()) do
    local ind = n. Text local
    btn = PlayersList[ind]
    btn.Activated:Connect(function()
        TargBox.Text = n. Name
    end)
 end
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    • 19
  8. Asked: May 12, 2022In:

    Error: access to dialectresolutioninfo cannot be null when ‘hibernate.dialect’ not set – Quick tips

    dhtutoria Expert
    This answer was edited.

    The cause: gene_name = no_headers.iloc[1:,[1]] This creates a DataFrame because you passed a list of columns (single, but still a list). When you later do this: gene_name[x] Now you have a Series object with a single value, so you can't hash the Series. Solution: You can resolve the error by creatinRead more

    The cause:

    gene_name = no_headers.iloc[1:,[1]]

    This creates a DataFrame because you passed a list of columns (single, but still a list). When you later do this:

    gene_name[x]

    Now you have a Series object with a single value, so you can’t hash the Series.

    Solution: You can resolve the error by creating Series from the start.

    gene_type = no_headers.iloc[1:,0]
gene_name = no_headers.iloc[1:,1]
disease_name = no_headers.iloc[1:,2]
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    • 12
  9. Asked: April 13, 2022In:

    Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to…

    dhtutoria Expert
    This answer was edited.

    import java.util.*; public class StudentScores { public static void main(String[] args) { Scanner scnr=new Scanner(System.in); final int SCORES_SIZE=4; int[] oldScores=new int[SCORES_SIZE]; int[] newScores=new int[SCORES_SIZE]; int i; for(i=0;i<oldScores.length;i++) { oldScores[i]=scnr.nextInt();Read more

    import java.util.*;
public class StudentScores
{
public static void main(String[] args) {
Scanner scnr=new Scanner(System.in);
final int SCORES_SIZE=4;
int[] oldScores=new int[SCORES_SIZE];
int[] newScores=new int[SCORES_SIZE];
int i;
for(i=0;i<oldScores.length;i++)
{
oldScores[i]=scnr.nextInt();
}
for(i=0;i<oldScores.length-1;++i) //iterating over oldScores array upto last but one element
{
newScores[i]=oldScores[i+1]; //storing oldScores[i+1] element in newScores[i]
if(i==oldScores.length-2) //if i is equal to array length-2
{
newScores[i]=oldScores[i+1];
newScores[i+1]=oldScores[0]; //last element of newScores is first element of oldScores
}
}

//printing final output this is optional
for(i=0;i<newScores.length;++i)
{
System.out.print(newScores[i]+"\t");
}
}
}
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    • 20
  10. Asked: April 13, 2022In:

    Define stubs for the methods called by the below main(). Each stub should print “FIXME: Finish…

    dhtutoria Expert

    Here is a suggestion for you import java.util.Scanner; public class MthdStubsStatistics { public static int getUserNum() { System.out.println("FIXME: Finish getUserNum()"); return -1; } public static int computeAvg(int userNum1, int userNum2) { System.out.println("FIXME: Finish computeAvg()"); returRead more

    Here is a suggestion for you

    import java.util.Scanner;

public class MthdStubsStatistics {

public static int getUserNum() {
System.out.println("FIXME: Finish getUserNum()");
return -1;
}

public static int computeAvg(int userNum1, int userNum2) {
System.out.println("FIXME: Finish computeAvg()");
return -1;
}

public static void main(String [] args) {
int userNum1;
int userNum2;
int avgResult;

userNum1 = getUserNum();
userNum2 = getUserNum();

avgResult = computeAvg(userNum1, userNum2);

System.out.println("Avg: " + avgResult);
}
}
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    • 17