Home/ dttutoria/Answers
  1. Asked: July 15, 2022In:

    How to fix: new transaction is not allowed because there are other threads running in the session.?

    Best Answer
    dttutoria Expert

    The cause:  I found that the foreach loops were to the culprit for that problem. Solution: Call EF with a return value into an IList<T> of that target type, then iterate through the IList<T>. The problem “new transaction is not allowed because there are other threads running in the sessiRead more

    The cause: 

    I found that the foreach loops were to the culprit for that problem.

    Solution: Call EF with a return value into an IList<T> of that target type, then iterate through the IList<T>. The problem “new transaction is not allowed because there are other threads running in the session.” will be fixed.

    For instance:

    IList<Client> clientList = from a in _dbFeed.Client.Include("Auto") select a;
foreach (RivWorks.Model.NegotiationAutos.Client client in clientList)
{
var companyFeedDetailList = from a in _dbRiv.AutoNegotiationDetails where a.ClientID == client.ClientID select a;
// ...
}
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    • 4
  2. Asked: July 15, 2022In:

    Which way to fix: net err_content_length_mismatch?

    Best Answer
    dttutoria Expert

    The cause: The data advertised in the HTTP Headers and the data delivered over the wire are clearly out of sync, which is the cause of this issue. Solution: A Solution for the error net err_content_length_mismatch: Expand the cache's capacity. Some files cannot fully load because of the tiny size ofRead more

    The cause: The data advertised in the HTTP Headers and the data delivered over the wire are clearly out of sync, which is the cause of this issue.

    Solution:

    A Solution for the error net err_content_length_mismatch:

    Expand the cache’s capacity. Some files cannot fully load because of the tiny size of the nginx proxy cache area by default. You can configure nginx to change the nginx cache area for a standard jQuery framework.

    http{
................................
proxy_buffer_size 128k;
proxy_buffers 32 128k;
proxy_busy_buffers_size 128k;
.............................
}
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  3. Asked: July 14, 2022In:

    mysqld_safe directory ‘/var/run/mysqld’ for unix socket file don’t exists – How to fix?

    Best Answer
    dttutoria Expert

    Solution: The answer is still extremely easy for the error: mysqld_safe directory ‘/var/run/mysqld’ for unix socket file don’t exists under ubuntu. mkdir -p/var/run/mysqld chown mysql:mysql/var/run/mysqld Next, carry out: /usr/bin/mysqld_safe - skip -grant -tables & Open a different shell to chaRead more

    Solution: The answer is still extremely easy for the error: mysqld_safe directory ‘/var/run/mysqld’ for unix socket file don’t exists under ubuntu.

    mkdir -p/var/run/mysqld 
chown mysql:mysql/var/run/mysqld

    Next, carry out:

    /usr/bin/mysqld_safe - skip -grant -tables &

    Open a different shell to change, then flush privileges when finished modification;

    Just stop the procedure that is running.

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  4. Asked: July 14, 2022In:

    How to solve the modulenotfounderror: no module named ‘google’ error?

    Best Answer
    dttutoria Expert

    The cause: The problem" modulenotfounderror: no module named ‘google’" most frequently occurs when the Google Python package is not installed on your system. Solution: There are several ways for that error: Solution 1. Simply install the google-api-python-client package. pip install --upgrade googleRead more

    The cause: The problem” modulenotfounderror: no module named ‘google’” most frequently occurs when the Google Python package is not installed on your system.

    Solution:

    There are several ways for that error:

    Solution 1. Simply install the google-api-python-client package.

    pip install --upgrade google-api-python-client

    Solution 2. Run both packages

    pip install google-cloud 
pip install google-cloud-vision

    Solution 3. Install this one:

    pip install google.cloud.bigquery 
pip install google.cloud.storage

    Solution 4. You should reinstall conda.

    sudo pip install conda
    pip install google

    Solution 5. Try this

    pip install protobuf
    pip install google-cloud-translate

    Here are some of my solution suggestions, hope to help you fix the above error.

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  5. Asked: July 14, 2022In:

    How to fix: method does not override method from its superclass?

    Best Answer
    dttutoria Expert

    The cause:  Although you are implementing a protocol method, it is not an override. That is the cause of the error occurrence "method does not override method from its superclass". Solution: Follow this way to solve your problem. Simply get rid of the override keyword. When your superclass implementRead more

    The cause: 

    Although you are implementing a protocol method, it is not an override. That is the cause of the error occurrence “method does not override method from its superclass”.

    Solution:

    Follow this way to solve your problem.

    Simply get rid of the override keyword. When your superclass implements a method as well, you are supplying an override that you want to change how the superclass implementation behaves.

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  6. Asked: July 12, 2022In:

    How to fix the issue: max virtual memory areas vm.max_map_count [65530] is too low, increase to at least [262144]?

    Best Answer
    dttutoria Expert

    The cause: Elasticsearch stores its indexes by default in a mmapfs directory. The operating system's default mmap count limits are probably too low, which could lead to out of memory exceptions. The error max virtual memory areas vm.max_map_count [65530] is too low, increase to at least [262144] appRead more

    The cause:

    Elasticsearch stores its indexes by default in a mmapfs directory. The operating system’s default mmap count limits are probably too low, which could lead to out of memory exceptions. The error max virtual memory areas vm.max_map_count [65530] is too low, increase to at least [262144] appeared as a result.

    Solution:

    You can raise the limitations on Linux by using the command as root below:

    sysctl -w vm.max_map_count=262144

    The vm.max_map_count option in /etc/sysctl.conf should be updated in order to set the value permanently. Run sysctl vm.max_map_count after restarting to confirm.

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  7. Asked: July 12, 2022In:

    How to solve the error: java.sql.sqlexception: before start of result set?

    Best Answer
    dttutoria Expert
    This answer was edited.

    The cause:  java.sql.sqlexception: before start of result set error occurs because of the following reason: The cursor jumps one line per time the next() method is used. Since it is initially situated before the first line, the first use of next() should make the first line the current line. The curRead more

    The cause: 

    java.sql.sqlexception: before start of result set error occurs because of the following reason:

    The cursor jumps one line per time the next() method is used. Since it is initially situated before the first line, the first use of next() should make the first line the current line. The cursor will advance one line with each call to next(). The cursor is active until the parent Statement object and child ResultSe object are closed.

    Solution: Prior to actually adding rs.next(), you should use rs.getString().

    Exact code:

    try

{

   resultSet.next();

   userID = resultSet.getInt("user_id");

   System.out.println(resultSet.toString()+"222");

}

catch  (SQLException e1) {  

    e1.printStackTrace();

}
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  8. Asked: July 12, 2022In:

    How to fix: java.sql.sqlexception: access denied for user ‘root’@’localhost’ (using password: yes)?

    Best Answer
    dttutoria Expert
    This answer was edited.

    The cause: The error java.sql.sqlexception: access denied for user ‘root’@’localhost’ (using password: yes) indicates that you entered the incorrect root password, which is why your database connection ended in failure. Solution: You can use this: GRANT ALL PRIVILEGES ON *.* TO root@localhost IDENTIRead more

    The cause: The error java.sql.sqlexception: access denied for user ‘root’@’localhost’ (using password: yes) indicates that you entered the incorrect root password, which is why your database connection ended in failure.

    Solution: You can use this:

    GRANT ALL PRIVILEGES ON *.* TO root@localhost IDENTIFIED BY %password% 
WITH GRANT OPTION;

    Use the command line or a GUI tool to carry it out. Replace %password% with the actual password. When building a database from scratch, you might use:

    Connection connection = DriverManager.getConnection(jdbc:mysql://localhost/?user=root&password=rootpassword);
PreparedStatement ps = connection.prepareStatement(CREATE DATABASE databasename);
int result = ps.executeUpdate();

    Follow the order of the example below:

    sudo mysql_secure_installation

sudo mysql

    Once you’ve logged in to MySQL, run the following instructions from the MySQL prompt:

    ALTER USER root@localhost IDENTIFIED WITH mysql_native_password BY password;
FLUSH PRIVILEGES;

    Check now to see if the root password is stored in the table.

    SELECT user,authentication_string,plugin,host FROM mysql.user;

    That can solve the problem.

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  9. Asked: July 12, 2022In:

    java.lang.illegalstateexception: could not execute method for android:onclick – How to fix?

    Best Answer
    dttutoria Expert

    The cause: A NullPointerException is noted in your logCat on line 246 of your code. I'll assume that's along these lines: public void onClick(View view){ switch (view.getId()){ case R.id.undoBtn: mView.onClickUndo(); break; case R.id.redoBtn: mView.onClickRedo(); break; The issue "java.lang.illegalsRead more

    The cause:

    A NullPointerException is noted in your logCat on line 246 of your code. I’ll assume that’s along these lines:

    public void onClick(View view){
switch (view.getId()){
case R.id.undoBtn:
mView.onClickUndo();
break;

case R.id.redoBtn:
mView.onClickRedo();
break;

    The issue “java.lang.illegalstateexception: could not execute method for android:onclick” is because you neglected to initialize mView. Instead, you initialize a local variable called myView in the onCreate method.

    Solution: The solution to your issue should be to assign that instance to mView.

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    • 0
  10. Asked: July 11, 2022In:

    How to solve this: java was started by returned exit code=1?

    Best Answer
    dttutoria Expert

    The cause: Your Java version may be incompatible, according to the error notice. Have you installed a JDK? And is the PC you are using 64-bit or 32-bit in terms of its architecture? Does it match the JDK version? Because it ought to be the same. Have you arranged the environment variable for the patRead more

    The cause:

    Your Java version may be incompatible, according to the error notice. Have you installed a JDK? And is the PC you are using 64-bit or 32-bit in terms of its architecture? Does it match the JDK version? Because it ought to be the same. Have you arranged the environment variable for the path as instructed in the repair for the JVM not found error?

    Solution:

    Do as the following way to fix java was started by returned exit code=1 error.

    1. Right-click the eclipse.ini file in the eclipse folder and choose edit.

    2. Next, add the lines: [path of the JDK should be where you have installed jdk]

    -XX:-UseCompressedOops
-vm
C:\Program Files\Java\jdk1.7.0_21\jre\bin\server\jvm.dll

    Note: It can’t be used in C:\Windows\System32

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