The displacement of an oscillating object as a function of time is shown in the figure.a)What...

Question

The displacement of an oscillating object as a function of time is shown in the figure.

a)What is the frequency?

b)What is the amplitude?

c)What is the period?

d)What is the angular frequency of this motion?

[su_box title="♦ Relevant knowledge" box_color="#2d6ff7" radius="1"]Frequency of an object that oscillates is the amount of oscillations made by the object oscillating second. However, the duration is the amount of duration required to complete an oscillation made by the object that is oscillating. The maximum displacement caused by an object that oscillates on either side of its mean location is known as the magnitude of the object that is oscillating.

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Damian O'Connor · Accepted Answer

Concepts and Reason

This problem was solved by the concept of characteristics of wave.

First, use the complete cycle's time period to calculate frequency. To calculate the amplitude A, you will need to find the highest wave height in a complete cycle. To calculate the value for angular frequency, you can use the expression of the angular frequency.

Fundamentals

The frequency of a wave can be defined as the number waves that pass through a particular point at a given time. Here's how to calculate frequency:

[katex]f = \frac{1}{T}[/katex]

T refers to the time of a complete cycle.

The amplitude of a Wave A refers to the highest height attained by a Wave in a Complete Cycle. It is measured in meters (m).

Here is the expression of the angular frequency:

[katex]\omega = 2\pi f[/katex]

f refers to the frequency of a wave.

(a) This is the time required to complete a cycle:

[katex]T = 16.0{ m{ s}}[/katex]

Substitute 16.0s for T in equation [katex]f = \frac{1}{T}[/katex]

[katex]\begin{array}{c}\f = \frac{1}{{16.0{ m{ s}}}}\\ = 0.0625{ m{ Hz}}\\end{array}[/katex]

(b) The amplitude of the wave is the maximum height that a wave can reach in a complete cycle. Hence,

[katex]A = 10.0{ m{ cm}}[/katex]

(c) The graph shows the following:

[katex]T = 16.0{ m{ sec}}[/katex]

(d) Here is the expression of the angular frequency:

[katex]\omega = 2\pi f[/katex]

f refers to the frequency of a wave.

Substitute 0.0625Hz for f in this expression.

[katex]\begin{array}{c}\\omega = 2\pi \left( {0.0625{ m{ Hz}}} ight)\\ = 0.39{ m{ rad/s}}\\end{array}[/katex]

Answer:

Part a, Wave frequency is 0.0625 Hz.

Part b, Waves have an amplitude of 10.0 cm

Part c, The wave takes 16.0 seconds to complete a cycle.

Part d, Waves have an angular frequency at 0.39 rad/s.

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