(Figure 1)Block 1. of mass m = 0.700 kg. is connected over an ideal (massless and frictionless) pulley to block 2 of mass m2

Question

Block 1, of mass m = 0.700 kg, is connected over an ideal (massless and frictionless) pulley to block 2 of mass my, as shown. For an angle of θ = 30.0° and a coefficient of kinetic friction between block 2 and the plane of μ = 0.350, an acceleration of magnitude α = 0.200 m/s² is observed for block 2.

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If the force acting on a body is more that the force of friction the body will alter its position. However, in the event that this force is be less than that of the friction force the body won't move. The friction force is based on how much friction coefficient.

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lyytutoria · Accepted Answer

Oliver Davis · Answer

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 Nove mow block fmiya txg.  Magsind. to, So Tv er uz -t- ta -0 Fox 2 - T- til' - Ru 2 t. -O, goo = ",4 e' Add equation (c) and  "13 - ms in p - AR>> =  ; m, 9 - ,asi>>- t@3 se' = " ma <> - "> (+) (5) - (-3%) >>, (+){ sch) = , (-2).|O, goo = "4,4 e" Add equation (c), and "13- msin p – AR>> = [ ] m, 9-,asi>>– t@3 se’ = " ma1>> | "> (+) (3) - (-3%) >> (+) Sch) =?, (-2). -So - 3o31m2 - +2 m, -- +7= 8-23 g. - 17
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