Momentum in an Explosion A giant "egg" explodes as part of a fireworks display. The egg...

Question

Momentum in an Explosion

A giant "egg" explodes as part of a fireworks display. The egg is at rest before the explosion, and after the explosion, it breaks into two pieces, with piece B moving in the positive x direction. The masses of both pieces are indicated in (Figure 1) , shown traveling in opposite directions.

A = 10kg

b = 30 kg

What is the magnitude of the momentum |p⃗A,i | of piece A before the explosion?

Express your answer numerically in kilogram meters per second.

During the explosion, is the magnitude of the force of piece A on piece B greater than, less than, or equal to the magnitude of the force of piece B on piece A?

greater than

less than

equal to

The component of the momentum of piece B, pBx,f , is measured to be +500 kg⋅m/s after the explosion. Find the component of the momentum pAx,f of piece A after the explosion.

Enter your answer numerically in kilogram meters per second.

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Based on Newton's laws even when an object is moving and remains in motion, it will remain so until it is affected by force. To measure the "motion" amount, the term momentum (the amount of weight and speed) is the term used. There are two kinds of momentum: angular and linear. Within each there are sub-components such as breaking down linear momentum into components of the x-axis and y-axis.

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Emily O'Brien · Accepted Answer

* The egg is resting, so the momentum P _A,i=m V _A,i =0.

* Before and after an explosion, momentum is preserved

P_A,i + P_B,i = P_A,f +P_B,f

0 = P_A,f + P_B,f

P_A,f = -P_B,f

Then,

P _A.f = -500 kg.m/s

* Since F= Δp ⁄ Δt

Both pieces should end with the same amount of momentum after the explosion. The forces between them must be equal in magnitude (but in opposite directions).

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