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Problem 5: Point charges located at 3, 8, and 11 cm along the x-axis are represented in the figure.
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What is the x-component of the force on the charge located at x = 8 cm given that q = 1.15 μc in N?
Numeric: A numeric value is expected and not an expression.
Fx =
The magnitude of the electric field due to the charge Q at a distance r from it is |E| = k|Q| ⁄ r2 |E|= k|Q| ⁄ r2 where k=8.99×109 Nm2 ⁄ C2 The electric field’s direction runs across the ray connecting the charge to the point at which it is determined in the event that the charge Q is positive nature. If not, the direction will be exactly the opposite in the event that Q is charged negative in nature.♦ Relevant knowledge
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