A 2300 kg truck has put its front bumper against the rear bumper of a 2400 kg SUV to give it a push. With the engine at full power and good tires on good pavement, the maximum forward force on the truck is 18,000 N.

**Part A**

What is the maximum possible acceleration the truck can give the SUV?

Express your answer to two significant figures and include the appropriate units.

*a* =

**Part B**

At this acceleration, what is the force of the SUV’s bumper on the truck’s bumper?

Express your answer to two significant figures and include the appropriate units.

F on truck =_{suv} |

*F=ma*, where

*F*is the force that acts on the object*A*is the object’s acceleration*M*is the weight that the item weighs

Concepts and ReasonThis problem can be solved by Newton’s second law.

Initially, you will write an expression to describe the force using Newton’s second law. Later, you will need to modify the expression to calculate the acceleration. To find the new force, you can substitute the acceleration value.

FundamentalsThe Newton’s second law is that the net force equals the product of the object’s mass and acceleration. This is the Newton’s second law.

F = mamrefers to mass, and refers to acceleration.(a)Rearrange equationa = F ⁄ mSubstitute 18,000 N to

Fand (2300 + 2400 kg) formin the equationa = F ⁄ ma = 18,000 N ⁄ (2300 kg + 2400 kg)

= 18,000 N ⁄ 47oo kg

= 3.83 m/s

^{2}(b)Substitute 3.83 m/s

^{2}for a and 2400 kg for m in the equationF = maF =(2400kg) (3.83 m/s

^{2}) = 9120NAns:Part AMaximum acceleration that the truck can give an SUV is 3.83 m/s

^{2}Part BThe force exerted by the bumper of an SUV on a truck’s bumper is 9120N.