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A metal bar is in the xy-plane with one end of the bar at the origin. A force

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Part A: What is the position vector r for the point where the force is applied? Enter the x and y components of the radius vector separated by a comma.

Part B: What are the magnitude of the torque with respect to the origin produced by F?

Part C: What are direction of the torque with respect to the origin produced by F?

Revelant knowledge

Torque: The strength and direction of the developed torque for an object are determined by the cross product of the force as well as the vector of location. The torque will vary with the distance perpendicular to the point where force is applied.

Part A:r = x i + y j = (3.58m i + 3.46m j)Part B:τ = r × F

τ = (3.58m i + 3.46m j) x ( 6.22N)i + ( -2.81N)j

τ = 31.581 N

Part C: Directions of Torque is z direction.