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A proton moves along the x-axis with v

*= 1.0 × 10*_{x}^{7}m/s.**Part A**

As it passes the origin, what are the strength and direction of the magnetic field at the (1 cm, 0 cm, 0 cm) position? Give your answer using unit vectors.

*Express your answer in terms of the unit vectors i, j, and k. Use the ‘unit vector’ button to denote unit vectors in your answer.*

Vector B = T

**Part B**

As it passes the origin, what are the strength and direction of the magnetic field at the (0 cm, 1 cm, 0 cm) position? Give your answer using unit vectors.

*Express your answer in terms of the unit vectors i, j, and k. Use the ‘unit vector’ button to denote unit vectors in your answer.*

Vector B = T

**Part C**

As it passes the origin, what are the strength and direction of the magnetic field at the (0 cm, -2 cm, 0 cm) position? Give your answer using unit vectors.

*Express your answer in terms of the unit vectors i, j, and k. Use the ‘unit vector’ button to denote unit vectors in your answer.*

Vector B = T

♦ Relevant knowledge

It is the Biot-Savart law, one of the fundamental laws of electromagnetism, connects the magnetic field created by a charged particle that is moving with a constant velocity or with a constant electric current. The field of magnetic energy generated can be measured directly in relation to the charge and charge that is generated by the particle, and in reverse proportional to the distance to the charge or current.

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## 1 Answer