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A rocket is launched straight up from the earth’s surface at a speed of 1.80×10^{4} .

If the rocket speeds up it is accelerating. The acceleration that the vehicle is constant with the amount of time it takes. If a bolt fell off the rocket at a certain time, we can determine the distance in relation to the final velocity of the moment the bolt fell.

This answer is a night launch, which means that the units have not been given. Suppose you’re talking m/s. The escape velocity v (esc) is 11286 m/s. You don’t subtract one velocity from another, as it’s energy that is conserved. So mv (final)2/2 =mv

_{0}^{2}/2 – mv[esc]^{2}/2. So v (final) = √(v_{0}^{2}-v(esc)^{2}).