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Home/ Questions/An electron with an initial speed of 580,000 m/s is brought to rest by an electric...
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Asked: April 10, 20222022-04-10T07:14:25+00:00 2022-04-10T07:14:25+00:00In: Physics

An electron with an initial speed of 580,000 m/s is brought to rest by an electric…

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An electron with an initial speed of 580,000 m/s is brought to rest by an electric field.

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Did the electron move into a region of higher potential or lower potential?

A) Because the electron is a negative charge and it slows down as it travels, it must be moving from a region of higher potential to a region of lower potential.

B) Because the electron is a negative charge and it slows down as it travels, it must be moving from a region of lower potential to a region of higher potential.

C) Because the electron is a positive charge and it accelerates as it travels, it must be moving from a region of lower potential to a region of higher potential.

D) Because the electron is a positive charge and it accelerates as it travels, it must be moving from a region of higher potential to a region of lower potential.

What was the potential difference that stopped the electron?

What was the initial kinetic energy of the electron, in electron volts?


Relevant knowledge

The energy conservation equation calculates the potential difference between the electron’s last and initial velocity. It is used to determine if one type of energy changes into another.

 

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  1. tonytutoria
    2022-04-10T07:16:33+00:00Added an answer on April 10, 2022 at 7:16 am


    An electron with an initial speed of 580,000 m/s is brought to rest by an electric...

    A) Since the electron is negatively charged, it must be moving from higher potential region to a lower potential region, because it is slowing down and will eventually stop Potential difference (9.1×10-31)(0)2_1( 9.1×10-31)(580000)-(-1.6×10-19) V V= 0.9566375 V V 0.96 V Initial kinetic energy, (0.511 MeV) 580000 m/s 300000000 m/s (0.511 eV) (10) (3.7377×10) 0.955 eV
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