. Advertisement .
..3..
. Advertisement .
..4..
......... ADVERTISEMENT ......... ..8..
Assume that I = 4.6A and d = 2.5cm .
– What is the strength of the magnetic field at the center of the loop in the figure?
– What is the direction of the magnetic field at the center of the loop?
Assume that I = 4.6A and d = 2.5cm .
– What is the strength of the magnetic field at the center of the loop in the figure?
– What is the direction of the magnetic field at the center of the loop?
♦ Relevant knowledge
The right-hand rule states that the direction of a magnetic field is determined by the curled fingers. The thumb indicates the direction of current.
r = d/2 = 2.5/2 = 1.25 cm = 0.0125 cm
Bnet = B(stright wire) + B(loop)
= mue*I/(2*pi*r) + mue*I/(2*r)
= 4*pi*10^-7*4.6/(2*pi*0.0125) +
4*pi*10^-7*4.6/(2*0.0125)
= 3.048*10^-4 T
You can find more information here
radius ,
r = 2.5/2
r = 1.25cm = 0.0125m
Strength of field, now
B = u0*I/ (2*pi*r), + u0*I/ (2r).
B= u0*4.6/(2*.0125) * (1/pi + 1)
B = 3.085 *10-4 T
The strength of the magnetic field at the center of the loop is 3.085 *10-4 T
the direction of field is INTO THE PAGE