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Home/ Questions/At 850 K, the equilibrium constant for the reaction 2SO2(g) + O2(g) ⇋ 2SO3(g)
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Asked: April 11, 20222022-04-11T18:47:37+00:00 2022-04-11T18:47:37+00:00In: Chemistry

At 850 K, the equilibrium constant for the reaction 2SO2(g) + O2(g) ⇋ 2SO3(g)

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At 850 K the equilibrium constant for the following reaction is Kc=15

2SO2(g) + O2(g) ⇋ 2SO3(g)

If we mix the following concentrations of the three gases, predict in which direction the net reaction will proceed toward equilibrium: Left, No Change, or Right.

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Reaction Quotient

Q is the reaction’s quotient. ( Q) is the quantity of reactants relative to the products during a specific moment in time. Similarly the equilibrium constant ( K) is the the ratio of products to reactants at the point of reaching equilibrium. Q is the measure of reaction at different times and is used to predict the final direction that the reaction’s progress in order to reach equilibrium.

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    Isabella Gagnon
    2022-04-11T18:47:40+00:00Added an answer on April 11, 2022 at 6:47 pm

    Reaction quotient Q = [SO3]2 / ([SO2]2[O2])

    If Q > Kc, the reaction will be weighted by products and the reaction proceeds in a direction backwards towards the reactants until it reaches equilibrium.

    If Q < Kc, then the reaction is weighted by reactants and the reaction will continue in a forward direction toward the equilibrium point of the product.

    Given:

    Kc = 15

    Part (a)

    Q = [SO3]2 / ([SO2]2[O2]) = (0.60)2 / ((0.20)2(0.60)) = 15

    As Q = Kc, the reaction is already in equilibrium. Therefore, there is no change.

    Part (b)

    Q = [SO3]2 / ([SO2]2[O2]) = (0.14)2 / ((0.70)2(0.70)) =0.057

    As Q < Kc, the reaction will proceed in the direction of forward (Right).

    Part (c)

    Q = [SO3]2 / ([SO2]2[O2])= (0.50)2 / ((0.20)2(0.10)) =62

    As Q > Kc, the reaction will continue in the reverse in the direction of (Left).

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