Home/ Questions/Learn how to fix error: attributeerror: 'int' object has no attribute 'append'
Next
Answered
Tracy Anderson
  • 9
Asked: 2022-05-18T20:49:30+00:00 In:

Learn how to fix error: attributeerror: ‘int’ object has no attribute ‘append’

  • 9

. Advertisement .

..3..

. Advertisement .

..4..

I get the “attributeerror: ‘int’ object has no attribute ‘append’” error as the title says. How can I fix it so the error goes away? Here is my detail:

import pyodbc,nltk,array,re,itertools
 cnxn = pyodbc.connect('Driver={MySQL ODBC 5.1 Driver};Server=127.0.0.1;Port=3306;Database=information_schema;User=root; Password=1234;Option=3;')
 cursor = cnxn.cursor()
 cursor.execute("use collegedatabase ;")
 cursor.execute("select * from sampledata ; ")
 cnxn.commit()
 s=[]
 j=[]
 x=[]
 words = []
 w = []
 sfq = []
 POS=[]
 wnl = nltk.WordNetLemmatizer()
 p = []
 clean= []
 l =[]
 tupletolist= []
 results = []
 aux = []
 regex = re.compile("\w+\.")
 pp = []
 array1=[]
 
 f = open("C:\\Users\\vchauhan\\Desktop\\tupletolist.txt","w")
 for entry in cursor:
  s.append(entry.injury_type),j.append(entry.injury_desc) 
 
 def isAcceptableChar(character):
  return character not in "~!@#$%^&*()_+`1234567890-={}|:<>?[]\;',/."
 
 
 from nltk.tokenize import word_tokenize
 from nltk.corpus import stopwords
 english_stops = set(stopwords.words('english'))
 for i in range(0,200):
  j.append(filter(isAcceptableChar, j[i]))
  w.append([word for word in word_tokenize(j[i].lower()) if word not in english_stops])
  for j in range (0,len(w[i])):
  results = regex.search(w[i][j])
  if results:
  str.rstrip(w[i][j],'.')
 for a in range(0 , 200):
  sfq.append(" ".join(w[a]))
 
 from nltk.stem import LancasterStemmer
 stemmer = LancasterStemmer()
 
 for i in range (0,200):
  pp.append(len(w[i]))
 
 for a in range (0,200):
  p.append(word_tokenize(sfq[a]))
  POS.append([wnl.lemmatize(t) for t in p[a]])
  x.append(nltk.pos_tag(POS[a]))
  clean.append((re.sub('()[\]{}'':/\-[(",)]','',str(x[a]))))
  cursor.execute("update sampledata SET POS = ? where SRNO = ?", (re.sub('()[\]{}'':/\-[(",)]','',str(x[a]))), a)
 
 for i in range (0,len(array1)):
  results.append(regex.search(array1[i][0]))
  if results[i] is not None:
  aux.append(i)
 
 f.write(str(w))

When I operated it, I received the error text:

Traceback (most recent call last):
  File "C:\Users\vchauhan\Desktop\regexsolution_try.py", line 37, in <module>
  j.append(filter(isAcceptableChar, j[i]))
 AttributeError: 'int' object has no attribute 'append'

I appreciate any help from you.

int object has no attribute append
Share

2 Answers

  1. Best Answer
    Expert

    The cause: When calling the append() method on an integer, the error “AttributeError: ‘int’ object has no attribute ‘append'” appears.

    Solution: J has been used as both an integer and a list. Only use j as an integer name; give the list a different name.

    j.append(filter(isAcceptableChar, j[i])) # j is not a list here,it is an int.
w.append([word for word in word_tokenize(j[i].lower()) if word not in english_stops])
for j in range (0,len(w[i])): # here j is an int
    • 0

  2. The following section of your code is worth a closer look: 

    for i in range(0,200):
 j.append(filter(isAcceptableChar, j[i]))
 w.append([word for word in word_tokenize(j[i].lower()) if word not in english_stops])
 for j in range (0,len(w[i])):

    You can see how .append is called on j, which you had initialized earlier with a list. Then you use it as a loop variable that is nested within the same loop.

    To avoid these errors, use meaningful and better variable names in your code. You can rename the loop variable or module-level list variable.

    • 12

Leave an answer

You must login to add an answer.

Need An Account,