Home/ Questions/Fixing the error: attributeerror: 'list' object has no attribute 'shape'
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Saira O'Neill
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Asked: 2022-05-18T20:51:48+00:00 In:

Fixing the error: attributeerror: ‘list’ object has no attribute ‘shape’

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I get the error message:

AttributeError: 'list' object has no attribute 'shape'

Has anyone ever faced this problem? How to troubleshoot the “attributeerror: ‘list’ object has no attribute ‘shape’.” The problem appears when I try to operate the following program:

def test(X, N):
  [n,T] = X.shape
  print "n : ", n
  print "T : ", T
 
 
 
 if __name__=="__main__":
 
  X = [[[-9.035250067710876], [7.453250169754028], [33.34074878692627]], [[-6.63700008392334], [5.132999956607819], [31.66075038909912]], [[-5.1272499561309814], [8.251499891281128], [30.925999641418457]]]
  N = 200
  test(X, N)
list object has no attribute shape
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2 Answers

  1. Best Answer
    Expert

    The cause: For the provided array, X.shape results a 3-item tuple, so [n, T] = X.shape generates a ValueError: ‘list’ object has no attribute ‘shape’.

    Solution: Shape attribute should be used with numpy.array.

    >>> import numpy as np
>>> X = np.array([
... [[-9.035250067710876], [7.453250169754028], [33.34074878692627]],
... [[-6.63700008392334], [5.132999956607819], [31.66075038909912]],
... [[-5.1272499561309814], [8.251499891281128], [30.925999641418457]]
... ])
>>> X.shape
(3L, 3L, 1L)
    • 0

  2. Alternativ, you could use np.shape(...)

    Take, for example: 

    import numpy as np
a=[1,2,3]

    np.shape(a) will output (3,)

    • 11

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