Home/ Questions/The best way to fix the attributeerror: 'nonetype' object has no attribute 'text' error
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Braxton Miller
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Asked: 2022-05-18T20:52:24+00:00 In:

The best way to fix the attributeerror: ‘nonetype’ object has no attribute ‘text’ error

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For the problem “attributeerror: ‘nonetype’ object has no attribute ‘text’.” I tried to fix it, but It doesn’t work and returns the result I want. Here is my program:

url = 'http://legis.senado.leg.br/dadosabertos/senador/4988/autorias'
 import requests
 from xml.etree import ElementTree
 
 response = requests.get(url, stream=True)
 response.raw.decode_content = True
 
 tree = ElementTree.parse(response.raw)
 
 root = tree.getroot()
 
 for child in root.iter('Materia'):
  if child.find('EmentaMateria').text is not None:
  ementa = child.find('EmentaMateria').text
 
  for child_IdMateria in child.findall('IdentificacaoMateria'):
  anoMateria = child_IdMateria.find('AnoMateria').text
  materia = child_IdMateria.find('NumeroMateria').text
  siglaMateria = child_IdMateria.find('SiglaSubtipoMateria').text
 
 
 
  print('Ano = '+anoMateria+' | Numero Materia = '+materia+' | tipo = '+siglaMateria+' | '+ementa)

and

---------------------------------------------------------------------------
 AttributeError Traceback (most recent call last)
 <ipython-input-70-77e5e1b79ccc> in <module>()
  11 
  12 for child in root.iter('Materia'):
 ---> 13 if not child.find('EmentaMateria').text is None:
  14 ementa = child.find('EmentaMateria').text
  15 
 
 AttributeError: 'NoneType' object has no attribute 'text'

has occurred. I’ve checked the entire command line, but still can’t find the mistake.

nonetype object has no attribute text
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2 Answers

  1. Best Answer
    Expert

    The cause: A call to an attribute out of an object which does not present or is not supported results in an exception known as an attribute error in the Python program.

    Solution: You should follow my way to fix attributeerror: ‘nonetype’ object has no attribute ‘text’:

    You should verify that child.find('EmentaMateria') is not None before determining if child.find('EmentaMateria').text is not None.

    Additionally, in order to prevent calling child.find('EmentaMateria') twice, you need also keep the returning value.

    Finally, whether child.find('EmentaMateria') returns None, you need to assign ementa to a default value because otherwise the following print function will reference an uninitialized variable.

    Alter:

    if child.find('EmentaMateria').text is not None:
ementa = child.find('EmentaMateria').text

    with:

    node = child.find('EmentaMateria')
if node is not None:
ementa = node.text
else:
ementa = None

    As an alternative, you can accomplish the same thing without a temporary variable by using the built-in function getattr:

    ementa = getattr(child.find('EmentaMateria'), 'text', None)
    • 0

  2. You can inspect the tags if you’re using the code to read an xml format file. In my case, there were some rogue tag at the end. I was able to remove them and the code worked as expected.

    • 14

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