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First, express the Ksp value for C2D3 using molar solubility.
C2D3 = (2x)2(3x)3= 108×5
Next, set the equation equal to your constant of solubility
9.14×10-9=108×5
x=9.67×10-3
The molar solubility of a compound is therefore 9.67×10-3