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..3..

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I get an error:

```
10:11: error: called object is not a function or function pointer
z=(x^y)+2(x&y);
^
```

when I try to run the following code:

```
z=x-~y-1;
printf("%d",z);
z=(x^y)+2(x&y);
printf("%d",z);
z=(x|y)+(x&y);
printf("%d",z);
z=2(x|y)-(x^y);
printf("%d",z);
```

How to fix the called object is not a function or function pointer. Please give me some good ideas.

The cause:`2(x&y)`

asks the compiler to call the function`2`

, passing an argument`x&y`

(just as`printf("hi")`

, it means “call“). However,`printf`

and pass an argument`"hi"`

`2`

is not a function, so it causes an error. A function call is a syntax call when you have`(`

followed by a value.Solution:Replace

by

and

by

If multiplication is what you planned, you need to have a multiplication operator.

Change

To

And

To

If multiplication is what your goal is, you will need the multiplication operator.