Home/ Questions/How to fix “called object is not a function or function pointer”
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William Rodriguez
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Asked: 2022-05-17T13:50:49+00:00 In:

How to fix “called object is not a function or function pointer”

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I get an error:

10:11: error: called object is not a function or function pointer 
 z=(x^y)+2(x&y); 
  ^

when I try to run the following code:

z=x-~y-1;
  printf("%d",z);
  z=(x^y)+2(x&y);
  printf("%d",z);
  z=(x|y)+(x&y);
  printf("%d",z);
  z=2(x|y)-(x^y);
  printf("%d",z);

How to fix the called object is not a function or function pointer. Please give me some good ideas.

function or function pointer
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2 Answers

  1. Best Answer
    Expert

    The cause:  

    2(x&y) asks the compiler to call the function 2, passing an argument x&y (just as printf("hi"), it means “call printf and pass an argument "hi" “). However,  2 is not a function, so it causes an error. A function call is a syntax call when you have ( followed by a value.

    Solution:  

    Replace

    z=(x^y)+2(x&y);

    by

    z=(x^y)+2*(x&y);

    and

    z=2(x|y)-(x^y);

    by

    z=2*(x|y)-(x^y);

    If multiplication is what you planned, you need to have a multiplication operator.

    • 14

  2. Change 

    z=(x^y)+2(x&y);

    To 

    z=(x^y)+2*(x&y);

    And 

    z=2(x|y)-(x^y);

    To 

    z=2*(x|y)-(x^y);

    If multiplication is what your goal is, you will need the multiplication operator.

    • 18

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