Home/ Questions/Simple solutions for the cannot invoke compareto(int) on the primitive type int error
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Kaden Thomas
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Asked: 2022-05-18T21:08:22+00:00 In:

Simple solutions for the cannot invoke compareto(int) on the primitive type int error

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I am working on java, but I found the following warning message:

Error Message: "Cannot invoke compareTo(int) on the primitive type
  int"

Is there any way to stabilize the issue “cannot invoke compareto(int) on the primitive type int”?
I read a lot of topics about this, but all of them were trying to install anything. Is this the correct way, or any recommendation for me?
Please find the beginning command below:

public voide addValue(int newNumber){
 int index = 0;
 
 while ((index < numbers.size()) && (numbers.get(index.compareTo(newNumber) ==-1))
  index++;
 
  numbers.add(index, NewNumber); 
 }

cannot invoke compareto(int)
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2 Answers

  1. Best Answer
    Expert

    The cause: In my opinion, the primitive type int isn’t a reference type like Integer, Primitive values cannot be used to call methods. You may easily compare two ints by typing index newNumber.

    Solution: Because primitive types are not Java objects, they lack methods. Use the matching class, please:

    Integer.toString(item.getId());
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  2. “Cannot invoke compareTo(int) on the primitive type int”

    It is important to realize that the primitive int type int, unlike Integer, is not a reference type. methods cannot be called on primitive values. If you need to compare two ints you can use index < newNumber as an example.

    Alternativly, you can use the static method comparison of Integer classes, such as Integer.compare(index, newValue). You don’t have to use methods to compare primitive value, you can do it “in place”.

    Notice: In other languages like Kotlin there is no such distinction. You can only have Int objects and call methods on them. Java makes this distinction. Study it and you’ll learn which approach to use.

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