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Home/ Questions/Construct a confidence interval of the population proportion at the given level of confidence. x =...
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kttutoria
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kttutoriaExpert
Asked: April 10, 20222022-04-10T08:11:46+00:00 2022-04-10T08:11:46+00:00In: Statistics-And-Probability

Construct a confidence interval of the population proportion at the given level of confidence. x =…

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Construct a confidence interval of the population proportion at the given level of confidence. x =...

Construct a confidence interval of the population proportion at the given level of confidence.

x = 860, n= 1100, 95% confidence 
  • The lower bound of the confidence interval is___
  • The upper bound of the confidence interval is___

(Round to three decimal places as needed.)


♦ Relevant knowledge
If an estimate is made that has two bounds or limits , it is known as the interval estimation that is derived from the parameters of the populace. This estimate of intervals is known as an interval of confidence. The interval guarantees that it contains the value of the parameter certain at the amount of significance.

If the numbers of values are high, it’s impossible to quantify every value to determine the percentage of the population. An individual sample of data is collected, and an interval of confidence, composed of a higher and lower boundary value, which most likely is the percentage of the population is constructed.

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    kttutoria Expert
    2022-04-17T05:20:53+00:00Added an answer on April 17, 2022 at 5:20 am

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  2. tonytutoria
    2022-04-10T09:01:01+00:00Added an answer on April 10, 2022 at 9:01 am


    Construct a confidence interval of the population proportion at the given level of confidence. x =...

    Sample size = n = 1100 Sample number of events = x = 860 Sample proportion = p = x/n = (860/1100) = 0.7818 (point estimate of population proportion) (1-0) Stanadard Error = = sqrt(0.7818*(1-0.7818)/1100) = 0.0125 n Confidence Level = 95 Significance Level = a = (100-95)% = 0.05 Critical value = z* = 1.96 [Using Excel =ABS(NORMINV(0.05/2,0,1))] Margin of Error = z* (standard error )= 1.96*0.0125 = 0.0244 Lower Limit =P – Margin of Error = 0.7818 -0.0244 = 0.757 Upper Limit =p + Margin of Error = 0.7818 +0.0244 = 0.806
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