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Construct the molecular orbital diagram for H2– and then identify the bond order.
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Bond order:
-
0
-
0.5
-
1
-
1.5
-
2
The molecular orbital configuration aids in determining the bonding order of molecules. The electrons fill molecules’ molecular orbits in the same way as they do in the orbitals of atoms. The bond order of molecules can be in the following manner: ......... ADVERTISEMENT ......... ..8.. Molecular Orbital Diagram: The Molecular Orbital diagram is among the most important methods to identify the electronic configuration as well as the electronic structure of the molecules. Molecular orbitals are generated by the orbitals of the atomic.
This problem was solved using a molecular orbital diagram.
To explain chemical bonding within a molecule, a molecular orbital diagram can be used. This diagram is based on the molecular orbital theory.
The molecular orbital theory states that a molecular orbital of a molecule can be formed from the combination of its atomic orbitals, and electrons are distributed among them.
Calculating the bond order for any molecule by using electrons that are distributed in a molecular orbital diagram is how it works.
[katex]{B_O}{\rm{ = }}\frac{1}{2}\left( {{n_{\rm{b}}} – {n_{\rm{a}}}} \right)[/katex] (1)
Here, [katex]{B_O}[/katex] is bond order, nb is the all electrons in bonding orbital. na is the total number of electrons in the antibonding orbital.
(1)
Fill [katex]3[/katex] with molecular orbital diagrams
(2)
The [katex]2[/katex] total number of electrons in bonding orbitals.
The total number of electrons in an antibonding orbital is [katex]1[/katex].
Here is the formula to calculate bond order:
[katex]{B_O}{\rm{ = }}\frac{1}{2}\left( {{n_{\rm{b}}} – {n_{\rm{a}}}} \right)[/katex]
Substitute [katex]2[/katex] for nb and 1 for na in the equation (1) to calculate the bond order.
[katex]\begin{array}{c}\\{B_O} = \frac{1}{2}\left( {2 – 1} \right)\\\\ = 0.5\\\end{array}[/katex]
Bond order for [katex]{{\rm{H}}_2}^ – [/katex] is 0.5
Answer:
Part 1
The [katex]{{\rm{H}}_2}^ – [/katex] molecular orbital diagram
The bond order for [katex]{{\rm{H}}_2}^ – [/katex] is 0.5