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Home/ Questions/Draw a Lewis structure for SO2 in which all atoms obey the octet rule
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kttutoria
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kttutoriaExpert
Asked: April 13, 20222022-04-13T03:34:49+00:00 2022-04-13T03:34:49+00:00In: Chemistry

Draw a Lewis structure for SO2 in which all atoms obey the octet rule

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  1. Draw a Lewis structure for SO2 in which all atoms obey the octet rule. Show formal charges. Do not consider ringed structures.
  2. Draw a Lewis structure for SO2 in which all atoms have a formal charge of zero. Explicitly showing the zero charges is optional. Do not consider ringed structures.

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♦ Relevant knowledge
The structure of compounds, atoms and ions are typically depicted using Lewis structures. These structures reveal the valence electrons in the atoms. In compounds the valence electrons could play a role in the formation of chemical bonds, or they could be non-bonding.

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    kttutoria Expert
    2022-04-23T16:25:08+00:00Added an answer on April 23, 2022 at 4:25 pm
    Concepts and Reason
    Calculate the total number of valances electrons in SO2​
    Use the following formula to calculate formal charge
    Formal charge of atom=Number of valance electrons –[Number of unshared valance electrons+1/2​ Number of shared valance electrons]​
    Fundamentals
    The Lewis structure is a diagram showing bonding between atoms within a molecule. It also shows the single pair of electrons that are present on each atom. Formal charge is the charge on an atom that does not include electronegativity variations.

    The periodic table’s Group 6A includes sulfur and oxygen atoms. 

    Total valance electrons in SO2​ = 6e–+2×6e–=18e–​

    Connect all atoms in the molecule to their valances.

    The correct Lewis structure using octets of all atoms is shown below:

    Below is a Lewis structure with formal charges at zero.

    ols.

    Answer:

    The following is the Lewis structure with the correct formal charges:

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  2. Elizabeth Tremblay
    2022-04-13T03:35:00+00:00Added an answer on April 13, 2022 at 3:35 am
    Concepts and Reason

    Calculate the total number of valances electrons in [katex]{\rm{S}}{{\rm{O}}_{\rm{2}}}[/katex]

    Use the following formula to calculate formal charge

    [katex]\begin{array}{l}\\{\rm{Formal charge of atom = Number of valance electrons}} – [{\rm{Number of unshared valance }}\\\\{\rm{ electrons + }}\frac{1}{2}{\rm{ Number of shared valance electrons]}}\\\end{array}[/katex]

    Fundamentals

    The Lewis structure is a diagram showing bonding between atoms within a molecule. It also shows the single pair of electrons that are present on each atom.

    Formal charge is the charge on an atom that does not include electronegativity variations.

    The periodic table’s Group 6A includes sulfur and oxygen atoms.

    [katex]\begin{array}{c}\\{\rm{Total valance electrons in S}}{{\rm{O}}_{\rm{2}}}{\rm{ = 6}}{{\rm{e}}^ – }{\rm{ + 2 \times 6}}{{\rm{e}}^ – }\\\\{\rm{ = 18 }}{{\rm{e}}^ – }\\\end{array}[/katex]

    Connect all atoms in the molecule to their valances. The correct Lewis structure using octets of all atoms is shown below:


    Below is a Lewis structure with formal charges at zero.


    ols.

    Ans:

    The following is the Lewis structure with the correct formal charges:


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