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Home/ Questions/Stabilizing the error with the best answers: expected primary expression before token c++.
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Caleb Morton
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Caleb Morton
Asked: May 18, 20222022-05-18T19:09:42+00:00 2022-05-18T19:09:42+00:00In: cpp

Stabilizing the error with the best answers: expected primary expression before token c++.

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Hi everyone, I’m learning about cpp. While working, I try undefined. As a result, I get the message:

void showInventory(player& obj) { // By Johnny :D
 for(int i = 0; i < 20; i++) {
  std::cout << "\nINVENTORY:\n" + obj.getItem(i);
  i++;
  std::cout << "\t\t\t" + obj.getItem(i) + "\n";
  i++;
 }
 }
 
 std::string toDo() //BY KEATON
 {
 std::string commands[5] = // This is the valid list of commands.
  {"help", "inv"};
 
 std::string ans;
 std::cout << "\nWhat do you wish to do?\n>> ";
 std::cin >> ans;
 
 if(ans == commands[0]) {
  helpMenu();
  return NULL;
 }
 else if(ans == commands[1]) {
  showInventory(player); // I get the error here.
  return NULL;
 }
 
 }
error: expected primary-expression before ')' token

What can I do about the “expected primary expression before token c++” issue? Is there a better approach?

token
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  1. Best Answer
    lyytutoria Expert
    2022-06-21T09:14:17+00:00Added an answer on June 21, 2022 at 9:14 am

    The cause:

    After looking over your program, I found that the function showInventory(player); is passing into a parameter, but it is invalid. Therefore, the error happens.

    Solution:

    You must pass into an object, not a parameter. Let’s see the following example:

    player p;
    showInventory(p);

    It has something like as:

    int main()
    {
    player player;
    toDo();
    }

    How terrible it is! Remember not to use the same name as your type for the object and you need to give the object a parameter so that it can be seen inside the function.

    int main()
    {
    player p;
    toDo(p);
    }

    And

    std::string toDo(player& p)
    {
    //....
    displayDirectory(p);
    //....
    }

    If you follow my above suggestions, you will solve your error successfully.

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  2. Aaron Rocher
    2022-05-25T20:51:35+00:00Added an answer on May 25, 2022 at 8:51 pm
    showInventory(player); // I get the error here.
    
    void showInventory(player& obj) { // By Johnny :D

    This means that player is a datatype, and showInventory expects a referance to a variable of type player.

    So the code is correct

     void showInventory(player& obj) { // By Johnny :D
     for(int i = 0; i < 20; i++) {
     std::cout << "\nINVENTORY:\n" + obj.getItem(i);
     i++;
     std::cout << "\t\t\t" + obj.getItem(i) + "\n";
     i++;
     }
     }
    
    players myPlayers[10];
    
     std::string toDo() //BY KEATON
     {
     std::string commands[5] = // This is the valid list of commands.
     {"help", "inv"};
    
     std::string ans;
     std::cout << "\nWhat do you wish to do?\n>> ";
     std::cin >> ans;
    
     if(ans == commands[0]) {
     helpMenu();
     return NULL;
     }
     else if(ans == commands[1]) {
     showInventory(myPlayers[0]); // or any other index,also is not necessary to have an array
     return NULL;
     }
    
    }
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