Home/ Questions/Stabilizing the error with the best answers: expected primary expression before token c++.
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Caleb Morton
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Asked: 2022-05-18T19:09:42+00:00 In:

Stabilizing the error with the best answers: expected primary expression before token c++.

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Hi everyone, I’m learning about cpp. While working, I try undefined. As a result, I get the message:

void showInventory(player& obj) { // By Johnny :D
 for(int i = 0; i < 20; i++) {
  std::cout << "\nINVENTORY:\n" + obj.getItem(i);
  i++;
  std::cout << "\t\t\t" + obj.getItem(i) + "\n";
  i++;
 }
 }
 
 std::string toDo() //BY KEATON
 {
 std::string commands[5] = // This is the valid list of commands.
  {"help", "inv"};
 
 std::string ans;
 std::cout << "\nWhat do you wish to do?\n>> ";
 std::cin >> ans;
 
 if(ans == commands[0]) {
  helpMenu();
  return NULL;
 }
 else if(ans == commands[1]) {
  showInventory(player); // I get the error here.
  return NULL;
 }
 
 }
error: expected primary-expression before ')' token

What can I do about the “expected primary expression before token c++” issue? Is there a better approach?

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2 Answers

  1. Best Answer
    Expert

    The cause:

    After looking over your program, I found that the function showInventory(player); is passing into a parameter, but it is invalid. Therefore, the error happens.

    Solution:

    You must pass into an object, not a parameter. Let’s see the following example:

    player p;
showInventory(p);

    It has something like as:

    int main()
{
player player;
toDo();
}

    How terrible it is! Remember not to use the same name as your type for the object and you need to give the object a parameter so that it can be seen inside the function.

    int main()
{
player p;
toDo(p);
}

    And

    std::string toDo(player& p)
{
//....
displayDirectory(p);
//....
}

    If you follow my above suggestions, you will solve your error successfully.

    • 0
  2. showInventory(player); // I get the error here.

void showInventory(player& obj) { // By Johnny :D

    This means that player is a datatype, and showInventory expects a referance to a variable of type player.

    So the code is correct 

     void showInventory(player& obj) { // By Johnny :D
 for(int i = 0; i < 20; i++) {
 std::cout << "\nINVENTORY:\n" + obj.getItem(i);
 i++;
 std::cout << "\t\t\t" + obj.getItem(i) + "\n";
 i++;
 }
 }

players myPlayers[10];

 std::string toDo() //BY KEATON
 {
 std::string commands[5] = // This is the valid list of commands.
 {"help", "inv"};

 std::string ans;
 std::cout << "\nWhat do you wish to do?\n>> ";
 std::cin >> ans;

 if(ans == commands[0]) {
 helpMenu();
 return NULL;
 }
 else if(ans == commands[1]) {
 showInventory(myPlayers[0]); // or any other index,also is not necessary to have an array
 return NULL;
 }

}
    • 23

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