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Lyra Wang
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Asked: 2022-05-18T19:10:31+00:00 In:

Quick handling of the ”expected unqualified-id before ‘{‘ token” error.

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I get the “expected unqualified-id before ‘{‘ token” error as the title says. How can I fix it so the error goes away? Here is my detail:

#ifndef RATIONAL_H
 #define RATIONAL_H
 
 using namespace std;
 
 struct ReducedForm
 {
  int iSimplifiedNumerator;
  int iSimplifiedDenominator;
 };
 
 //I have a class here for the other stuff in the program
 #endif
#include <iostream> 
 #include "rational.h" 
 using namespace std;
 
 void Rational :: SetToReducedForm(int iNumerator, int iDenominator)
 {
 int iGreatCommDivisor = 0;
 
 iGreatCommDivisor = GCD(iNumerator, iDenominator);
 
 //The next 2 lines is where i get the error
 ReducedForm.iSimplifiedNumerator = iNumerator/iGreatCommDivisor;
 ReducedForm.iSimplifiedDenominator = iDenominator/iGreatCommDivisor;
 };

When I operated it, I received the error text:

error: expected unqualified-id before ‘.’ token

I appreciate any help from you.

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2 Answers

  1. Best Answer
    Expert

    The cause:

    From your program, I realize that not all the struct’s members are static and you are accessing statically to the struct with a . , but it’s illegal, it should be ::.

    Solution:

    ReducedForm is the name of the struct; you must create an object (for example the struct or class) to use it. Let’s follow these steps:

    ReducedForm MyReducedForm;
MyReducedForm.iSimplifiedNumerator = iNumerator/iGreatCommDivisor;
MyReducedForm.iSimplifiedDenominator = iDenominator/iGreatCommDivisor;
    • 0

  2. The . :: is not being used to access the struct statically. Neither are its members static. You can either instantiate ReducedForm.

    ReducedForm rf;
rf.iSimplifiedNumerator = 5;

    Change the static members like this:

    struct ReducedForm
{
 static int iSimplifiedNumerator;
 static int iSimplifiedDenominator;
};

    You must use :: to access members. I strongly doubt that you’re trying to access . in this case.

    • 15

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