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Home/Questions/For each compound below, click in the box to toggle the direction of bond polarity.
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lizawr
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lizawr
Asked: April 11, 20222022-04-11T19:02:40+00:00 2022-04-11T19:02:40+00:00In: Chemistry

For each compound below, click in the box to toggle the direction of bond polarity.

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For each compound below, click in the box to toggle the direction of bond polarity (leave the box blank for a nonpolar bond).

For each compound below, click in the box to toggle the direction of bond polarity (leave...


♦ Relevant knowledge

Polar and Nonpolar Bonds

If both atoms possess identical electronegativities, they’ll pull the electrons that are in the middle toward each other equally. This will create a nonpolar bond which is a kind of covalent bond where the electrons are divided equally. This kind of bond is quite frequent, particularly between two atoms from the same element like oxygen or hydrogen.

If one element is more electronegative than the other one, it will pull more on the shared electrons within the central atom, forming an Polar bond. Polar bonds are covalent bond where electrons are shared in a different way.

bond polaritynonpolar bond
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    Lauren Anderson
    2022-04-12T00:14:23+00:00Added an answer on April 12, 2022 at 12:14 am
    Concepts and Reason

    A polar covalent bond is made between atoms that have different electron negativeities. Non-polar covalent bonds will be formed between atoms with the same electron negativities.

    Identify the atoms that form the bond and the electronegativity atoms.

    Bond polarity is caused by the difference in electron negativity among the atoms. The symbol \to represents bond polarity.

    Fundamentals

    The formation of negative and positive charges on atoms is caused by a chemical bond between atoms that have an unequal share of electrons. This phenomenon is known as bond polarity.

    Nature is more electronegative for halogens that are Group 7A elements in the periodic table.

    The {\rm{Br}} – {\rm{Br}} molecule

    The molecule {\rm{H}} – {\rm{Cl}}

    The molecule {\rm{F}} – {\rm{C}}{{\rm{H}}_3}Ans

    LA
H-CI
Br-Br
F-CH,

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