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This problem is based upon the concepts of conjugate acid, and conjugate base.
On losing one proton, a chemical species can create a negatively charged or neutral substance. This is known as its conjugate base. It is generally anionic or negative in nature. However, if it gains one proton, it creates a species that is either positively charged (or neutral) in nature. This species is known as conjugate acid.
With the help of protonation or deprotonation, conjugate base and conjugate acids can be determined for any chemical species.
Formation of a conjugate base for [katex]{\rm{HSO}}_4^ – [/katex]
[katex]{\rm{HSO}}_4^ – \to {{\rm{H}}^ + } + \;{\rm{SO}}_4^{ – 2}[/katex]
The conjugate base is [katex]{\rm{SO}}_4^{ – 2}[/katex].
The formation of conjugate acids of [katex]{\rm{HSO}}_4^ – [/katex]
[katex]{\rm{HSO}}_4^ – {\rm{ + }}\;{{\rm{H}}^ + } \to {{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}[/katex]
The conjugate acid will then be [katex]{{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}[/katex]Ans
Formula for [katex]{\rm{HSO}}_4^ – [/katex] conjugate base
Formula for [katex]{\rm{HSO}}_4^ – [/katex] conjugate base