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Give the formula of the conjugate base of HSO4– .
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Give the formula for the conjugate acid of HSO4–.
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♦ Relevant knowledge
Bronsted-Lowry acid can be described as an ion or molecule which is distinguished by two key features. It is the first to contain an ionic bond that is covalent, namely the “H-X” bond in which “X” is a different atom which is is not hydrogen. Another aspect is that this bond is able to be dissociated asymmetrically to an extent in aqueous solutions, so that water molecules are able to take in the hydrogen ionized (proton) and release it. We refer to this “H-X” bond dissociation as a deprotonation process , and it creates the conjugate base product.
This problem is based upon the concepts of conjugate acid, and conjugate base.
On losing one proton, a chemical species can create a negatively charged or neutral substance. This is known as its conjugate base. It is generally anionic or negative in nature. However, if it gains one proton, it creates a species that is either positively charged (or neutral) in nature. This species is known as conjugate acid.
With the help of protonation or deprotonation, conjugate base and conjugate acids can be determined for any chemical species.
Formation of a conjugate base for [katex]{\rm{HSO}}_4^ – [/katex]
[katex]{\rm{HSO}}_4^ – \to {{\rm{H}}^ + } + \;{\rm{SO}}_4^{ – 2}[/katex]
The conjugate base is [katex]{\rm{SO}}_4^{ – 2}[/katex].
The formation of conjugate acids of [katex]{\rm{HSO}}_4^ – [/katex]
[katex]{\rm{HSO}}_4^ – {\rm{ + }}\;{{\rm{H}}^ + } \to {{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}[/katex]
The conjugate acid will then be [katex]{{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}[/katex]Ans
Formula for [katex]{\rm{HSO}}_4^ – [/katex] conjugate base
Formula for [katex]{\rm{HSO}}_4^ – [/katex] conjugate base