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Give the structure that corresponds to the following molecular formula and 1H NMR spectrum: The magenta…

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Give the structure that corresponds to the following molecular formula and 1H NMR spectrum:
                                                        chemical shift, Hz

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                                                              chemical shift ppm, (ð)
The magenta numbers in the spectrum are the relative integrals in arbitrary units.
♦ Relevant knowledge

NMR is a form of nuclear magnetic resonance (NMR) spectroscopy. It is a technique that uses spectroscopy employed to determine the chemical structure or their bonding sequences and also the purity of the compound. The Proton (or the H) NMR is used to examine the signals that are produced by the hydrogen contained within the molecule, which are displayed in spectrum. NMR is employed in numerous circumstances, but is commonly used in the process of synthesizing new compounds or purifying or separating compounds to ensure the high purity.

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    Concepts and Reason

    1H NMR Spectroscopy:

    Nuclear magnetic resonance (NMR) spectroscopy is one of the techniques in the analytical chemistry that is widely used to determine the purity of sample and to predict the structure of the organic compounds.

    The NMR spectrum is phenominal. It is when frequency of nuclei in atoms (sample), resonates with frequency magnetic field.

    HNMR Spectroscopy determines the different types of hydrogens (chemically non-equivalent hydrogens) present in a molecule.

    Fundamentals

    1HNMR Spin-Spin Coupling Designs:

    Number of hydrogens that are chemically non-equivalent to each other

    n

    Number of peaks

    ()

    Splitting Name

    Ratio of peak heights

    0

    1

    Singlet

    1

    2

    Doublet

    2

    3

    Triplet

    3

    4

    Quartet

    1:33:1

    Here’s how to calculate the degree unsaturation

    _2C+N-H-X+2 where, DoU is the degree of unsaturation, C is the number of carbons, N is the number of nitrogens, H is

    The given molecular formula : CHO Doll-(2x7)+0-16-0+2 2 Dou - 14–16+2 DoU =0(It has no double bond)

    The H NMR spectral data is given below:

    Chemical shift

    Multiplicity

    Around 0.9ppm

    Triplet

    Around 1.38ppm

    quartet

    Around 1.42ppm

    Singlet

    Chemical shift – 1.42ppm: The H NMR spectra shows quartet at 1.42ppm is due to the splitting of three hydrogens attached to carbon and there are three identical methyl groups.

    Example: 1.42ppm (quartet) HC-CH3

    Chemical shift – 1.38ppm: The singlet peak is observed at 1.38ppm disappear after shaking with proton at group of tertiary alcohol.

    Chemical shift – 0.9ppm: The H NMR spectra shows triplet at 0.9ppm is due to the splitting of two hydrogens attached to carbon shows this peak and three identical ethyl groups.

    Example: 0.9 ppm (triplet) H2C— CH3

    The compound therefore has one alcoholic and three identical CH,CH, groups attached the the tertiary atom of carbon.

    Below is the structure of the compound, with an assignment of chemical shifts values.

    0.9ppm (triplet) 1.42ppm (quartet) HO-CH2 1.42ppm (quartetty * Hąc—¢—OH C 0.9ppm (triplet) CH 1.42ppm (quartet) 0.9ppm (tripl

    Ans:

    The structure of the organic compound given is

    CH2CH3 H3CH2C—C—OH CH2CH3

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