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- Show the directions of the forces – repulsive for ke charges, attractive far opposite charges- on the piciorial representation, .
- When possible, do graphical vector addition on the pictorial representation. Although not , it tells you the type of answer you should expect
- Write each force vector in terms of its x and y components, and then add the components to find the net force. Use the pictorial representation to determine which components are positive and which are negative.
ASSESS: Check that your resut has the correct units, is reasonable, and answers the quesion.
Learning Goal: To practice Problem-Solving Strategy 22.1 for electric force problems.
Two charged particlas, with charges q1=q, and q2=4q, are located on the x axis separated by a distance of 2.00 cm. A third charged particle, with charge q3=q, is placed on the x axis such that the magnitude of the force that charge 1 exerts on charge 3 is equal to the force that charge 2 exerts on charge 3. Find the position of charge 3 when q=1.00 nC
Part A: Which of the following sketches represents a possible configuration for this problem?
Enter the letter(s) indicating the correct graph(s) in alphabetical order. For example, if you think that A and B are correct, enter AB.
Relevant knowledge
An magnitude can be described as the measurement or the absolute value of a number. The magnitude is expressed as an integer positive. Simply put it is the amount of an amount. For instance how big an earthquake calculated on the Richter scale, typically varies in between 1-10, and is the measurement of the magnitude that the seismic event. A magnitude of 8 poses more hazardous than an earthquake that is 3 magnitude.
The electrostatic force may be created through
F = K*Q1*Q2/R2
The force charges 1 exerts on the charge will result in
F13 = k*q1*q3/d1^2
in which d1 represents the distance that exists between q1 and q3
Charge 2 forcefully on charge 3 now.
F23 = k*q2*q3/d2^2
n which d2 represents the distance that exists between q2 and q3
In light of that
|F13| = |F23|
k*q1*q3/d1^2 = k*q2*q3/d2^2
Based on that
q1 = q & q2 = 4q & q3 = q, So
k*q*q/d1^2 = k*4q*q/d2^2
(d2/d1)^2 = 4
2/d1 = sqrt 4, which is 2
d2 = 2*d1
distance between q2 and equals twice of the distance between them.
Q1 and q3
In another way in other words, d2 > d1
In the configurations above, only A and C is able to follow the previous relation.
=> The Correct Solution: A, C
The electrostatic force can be generated by
F = k*Q1*Q2/R2
The force that charge 1 exerts upon charge 3 will be
F13 = k*q1*q3/d1^2
where d1 is the distance between q1 & q3
Force charge 2 on charge 3 now
F23 = k*q2*q3/d2^2
where d2 is the distance between q2 & q3
Given that,
|F13| = |F23|
k*q1*q3/d1^2 = k*q2*q3/d2^2
Given that
q1 = q & q2 = 4q & q3 = q, So
k*q*q/d1^2 = k*4q*q/d2^2
(d2/d1)^2 = 4
d2/d1 = sqrt 4, = 2
d2 = 2*d1
distance between q2 and q3 = twice of distance between
q1 and q3
In other words, d2 > D1
In the above-described configurations, only A adC follows the above relation.
Correct Answer: AC
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