<div class=""> HClO is a weak acid (Ka= 4.0 x 10-8 ) and so the salt NaClO acts as a weak base. What is the pH of a solution that is 0.036 M in NaClO at 25°C? <img class="content-img aligncenter" src="https://ittutoria.net/wp-content/uploads/2022/04/HClO-is-a-weak-acid-Ka-4.0x10^-8-and-so-the-salt-NaClO-acts-as-a...jpg" /> [su_box title="&diams; Relevant knowledge" box_color="#2d6ff7" radius="1"]Solving for the pH of NaClO NaClO or sodium hypochlorite act as a weak basis in the solution. The substance is instabil and can react rapidly when heated. In an aqueous solution, when paired HClO the pH of its solution can be determined by first determining the value that is its constant for dissociation Kb. Then , solve the concentration of its hydroxide ions and, based on that, pOH can be easily solved. Utilize the relationship between both the value of pH and the pOH value to find the pH. </div><div>[/su_box]</div>

Concentration of N2OC1 = 0.03 M K of OCI. 1.0x1014 4.0x108 = 2.5x107 Base hydrolysis reaction OCI H.O ->> OCI H.O ->> OCI H.O ->> OCI H.O ->> OCI H.O. 0.036 (m)= 0.036 2.5x107x0.036 [on GoSr 2.5x10 0.036] x = 0.9x10 x =V0.9x10-8 =9.98 pH = 4.02 pH 3.05 log (9.5) = 14.02 -5.00 log (9.5) = 14.02 = -).

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Asked: April 13, 20222022-04-13T05:46:38+00:00 2022-04-13T05:46:38+00:00In: Chemistry

HClO is a weak acid (Ka= 4.0×10^-8) and so the salt NaClO acts as a weak base.

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HClO is a weak acid (K_a= 4.0 x 10^-8 ) and so the salt NaClO acts as a weak base. What is the pH of a solution that is 0.036 M in NaClO at 25°C?

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Solving for the pH of NaClO

NaClO or sodium hypochlorite act as a weak basis in the solution. The substance is instabil and can react rapidly when heated. In an aqueous solution, when paired HClO the pH of its solution can be determined by first determining the value that is its constant for dissociation Kb. Then , solve the concentration of its hydroxide ions and, based on that, pOH can be easily solved. Utilize the relationship between both the value of pH and the pOH value to find the pH.

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Barbara O'Brien
2022-04-13T05:49:46+00:00Added an answer on April 13, 2022 at 5:49 am
Concentration of N2OC1 = 0.03 M K of OCI. 1.0×1014 4.0×108 = 2.5×107 Base hydrolysis reaction OCI H.O ->> OCI H.O ->> OCI H.O ->> OCI H.O ->> OCI H.O. 0.036 (m)= 0.036 2.5x107x0.036 [on GoSr 2.5×10 0.036] x = 0.9×10 x =V0.9×10-8 =9.98 pH = 4.02 pH 3.05 log (9.5) = 14.02 -5.00 log (9.5) = 14.02 = -).
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