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How many ions are present in 30.0 mL of 0.600M Na2CO3 solution?
♦ Relevant knowledgeIf the molarity or the concentration of a chemical compound as well as the volume of it are also provided as well, then the amount of moles is calculated easily using the product of the volume and the concentration. In general, the amount of moles for chemical compounds is determined with a mole International normal unit.
0.600mol/L *1L/1000mL* 30.0mL =0.018 moles Na2CO3.
For every mole of Na2CO3 solution, there are three moles of ions (2 Na+ & 1 CO3-), so triple it!
0.018×3=0.054moles ions. You can multiply this number by Avogadro’s number 6.02×1023
3.25×1022 Ions