Home/ Questions/How to solve no content to map due to end-of-input error?
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Daryl Schmidt
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Asked: 2022-07-15T10:31:23+00:00 In:

How to solve no content to map due to end-of-input error?

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Using the Jackson parser package, I am attempting to parse this JSON string, however I am getting mapping-exceptions that state: no content to map due to end-of-input.

com.fasterxml.jackson.databind.JsonMappingException: No content to map due to end-of-input
 at [Source: java.io.StringReader@421ea4c0; line: 1, column: 1]

Why do we encounter such exceptions?

How can I determine the reason for this exception? Help me fix it, please. Thanks a lot.

I’m attempting to parse using the method below:

StatusResponses loginValidator = null;
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(Feature.AUTO_CLOSE_SOURCE, true);
try {
String res = result.getResponseAsString();//{"status":"true","msg":"success"}
loginValidator = objectMapper.readValue(result.getResponseAsString(), StatusResponses.class);
} catch (Exception e) {
e.printStackTrace();
}

StatusResponse class

@JsonInclude(JsonInclude.Include.NON_NULL)
@JsonPropertyOrder({ "status","msg" })
public class StatusResponses {
@JsonProperty("status")
public String getStatus() {
return status;
}
@JsonProperty("status")
public void setStatus(String status) {
this.status = status;
}
@JsonProperty("msg")
public String getMessage() {
return message;
}
@JsonProperty("msg")
public void setMessage(String message) {
this.message = message;
}
@JsonProperty("status")
private String status;
@JsonProperty("msg")
private String message;
private Map<String, Object> additionalProperties = new HashMap<String, Object>();
@JsonGetter
public Map<String, Object> getAdditionalProperties() {
return additionalProperties;
}
@JsonSetter
public void setAdditionalProperties(Map<String, Object> additionalProperties) {
this.additionalProperties = additionalProperties;
}
}
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1 Answer

  1. Best Answer
    Expert

    The cause:  In most cases, the issue was brought on by my sending the ObjectMapper.readValue call a null InputStream. In another scenario, the client side was the issue. I didn’t shut the server stream I was writing to by accident.

    Solution:

    • Do not pass an empty InputStream to the call.
    • Closed stream and it will worked successful
    OutputStream out = new BufferedOutputStream(urlConnection.getOutputStream()); 
out.write(jsonstring.getBytes()); 
out.close() ; //This is what I did
    • Other way: Just run this
    import com.fasterxml.jackson.core.JsonParser.Feature;
import com.fasterxml.jackson.databind.ObjectMapper;
StatusResponses loginValidator = null;
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(Feature.AUTO_CLOSE_SOURCE, true);
try {
String res = result.getResponseAsString();//{"status":"true","msg":"success"}
loginValidator = objectMapper.readValue(res, StatusResponses.class);//replaced result.getResponseAsString() with res
} catch (Exception e) {
e.printStackTrace();
}
    • 2

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