Home/ Questions/Is it okay to fix the indexerror: index 0 is out of bounds for axis 0 with size 0 problem?
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Joyce Roy
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Asked: 2022-05-18T19:28:41+00:00 In:

Is it okay to fix the indexerror: index 0 is out of bounds for axis 0 with size 0 problem?

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As advised, I used some code samples in another forum, but it could not improve the problem. My question is the “indexerror: index 0 is out of bounds for axis 0 with size 0” in python – how to solve it? The command line is:

x = np.linspace(1735.0,1775.0,100)
 column1 = (data[0,0:-1]+data[0,1:])/2.0
 column2 = data[1,1:]
 x_column1 = np.zeros(x.size+2)
 x_column1[1:-1] = x
 x_column1[0] = x[0]+x[0]-x[1]
 x_column1[-1] = x[-1]+x[-1]-x[-2]
 experiment = np.zeros_like(x)
 for i in range(np.size(x_edges)-2):
  indexes = np.flatnonzero(np.logical_and((column1>=x_column1[i]),(column1<x_column1[i+1])))
  temp_column2 = column2[indexes]
  temp_column2[0] -= column2[indexes[0]]*(x_column1[i]-column1[indexes[0]-1])/(column1[indexes[0]]-column1[indexes[0]-1])
  temp_column2[-1] -= column2[indexes[-1]]*(column1[indexes[-1]+1]-x_column1[i+1])/(column1[indexes[-1]+1]-column1[indexes[-1]])
  experiment[i] = np.sum(temp_column2) 
 return experiment

and the result:

index 0 is out of bounds for axis 0 with size 0

What does the message mean? Can you advise me to fix it? If you have other better answers, leave them in the answer box below.

numpy
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2 Answers

  1. Best Answer
    Expert

    The cause: The cause of the “indexerror: index 0 is out of bounds for axis 0 with size 0” is that we are attempting to access an index (in this case, at position 0), but it is not there (i.e., it doesn’t exist as we have a size 0 array).

    Solution: Because such an array is essentially meaningless and unable to be used to store anything. As a result, you must follow the traceback in your code, find the area where an array or tensor of size 0 is being created, and fix it.

    1. Utilize a try-except block.
    2. Make sure the array’s size is not zero by: 
      if x.size != 0:
    • 0

  2. numpy index and dimension numbering begins with 0. axis 0 is the first dimension. A dimension can also have length (size), in numpy. This is the simplest example: 

    In [435]: x = np.zeros((0,), int)
In [436]: x
Out[436]: array([], dtype=int32)
In [437]: x[0]
...
IndexError: index 0 is out of bounds for axis 0 with size 0

    It also happens if x = np.zeros((0,5), int) is a 2d array that has 0 rows and 5 columns.

    You are now creating an array of size 0 in your code.

    It is normal to ask about errors and tell us the location.

    You should also print the shape and possibly the dtype of any suspected variables when you are trying to debug problems like these.

    pandas

    How to fix the error

    1. Use a try-except block
    2. Verify that the array’s size is not less than 0

      • if x.size != 0:
    • 8

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