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Indicate whether or not each of the following structures is considered to be aromatic.
♦ Relevant knowledgeIn order for a compound to be aromatic, in accordance with Huckel’s rules, it must be in full cyclic conjugation, and the amount of pi electrons within the ring must be of form 4n+2, with n being an integer.
This problem was solved by using Huckel’s rule to determine the aromatic compound.
The compound which has continuous cyclic structure with (4n+2)π electrons, where n= 0,12… are called aromatic compound.
The compound with a continuous cyclic structure and (4n)π elements, where n=0,12… are called Anti-aromatic.
Non-aromatic compounds are those that lack planarity.
Huckel’s rule applies to aromatic compounds.
The Huckel’s rule states that compound should be stratified under the following conditions.
1.Compound contains (4n+2)π electrons in their structure where n is the integer number like 0,1, 2 etc.
2.Carbons of compound should be in sp2 hybridization state.
3.Compound must have cyclic properties. Non-cyclic compounds are not aromatic.
4.Compound includes conjugation refers to alternative single or double bonds
These compounds have the following structure:
Combine A
Compound B
Three double bonds in compound A total six π electrons.
Compound B The 4 electrons from the double bonds would be the electrons, and the single oxygen pair would be the electron involved in conjugation. So total 6π electrons.
Combine A
Because it is not a planar molecule, compound A cannot be considered an example of an aromatic compound.
Compound B
An example of an aromatic compound is compound B.
Ans:
This means that compound B is aromatic and A is not.