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Home/ Questions/How can I handle -iso c++ forbids comparison between pointer and integer?
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Emma Caron
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Emma Caron
Asked: May 12, 20222022-05-12T09:53:33+00:00 2022-05-12T09:53:33+00:00In: cpp

How can I handle -iso c++ forbids comparison between pointer and integer?

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Recently, I ran some of my cpp code, and it gave the warning text:

error: ISO C++ forbids comparison between pointer and integer

While searching, I realized that some people added some command lines in my sample above. But I don’t think it is the best way to correct the problem – iso c++ forbids comparison between pointer and integer How would you explain this trouble? or Is there a better way? Below is the detail of the command that I used:

#include <iostream>
 #include <string>
 using namespace std;
 bool accept()
 {
  cout << "Do you want to proceed (y or n)?\n";
  char answer;
  cin >> answer;
  if (answer == "y") return true;
  return false;
 }
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    lyytutoria Expert
    2022-06-02T09:57:20+00:00Added an answer on June 2, 2022 at 9:57 am

    The cause: The reason of this error is:

    if (answer == "y")

    Because single quotes represents a char constant, not double quotes.

    Solution: There are two ways to fix this error:

    1, You can use string answer; instead of  char

    2, Another way is fix as below:

    if (answer == 'y') ...

    (Remember single quotes instead of double, represents a char constant)

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  2. Gabin Levasseur
    2022-05-25T19:40:30+00:00Added an answer on May 25, 2022 at 7:40 pm

    It is necessary to convert double quotation marks into singles. ie. if (answer == 'y') returns true;

    Here is some info on String Literals in C++: http://msdn.microsoft.com/en-us/library/69ze775t%28VS.80%29.aspx

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