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**Part A**: At what angle θ_{1} to the normal would the first dark ring be observed?

answer is 442^{o}

**Part B**: Suppose that the light from the pinhole projects onto a screen 3 meters away. What is the radius of the first dark ring on that screen? Notice that the angle from Part A is small enough that sinθ≈tanθ .

Answer is 23.2mm

**Part C**: The first dark ring forms the boundary for the bright Airy disk at the center of the diffraction pattern. What is the area A of the Airy disk on the screen from Part B? answer must be in mm^{2}

^{-1}(1.22 λ /d) ……………..(1)^{-3}m^{-9}^{0}^{0}) = 0.0232m = 23.2mm^{2}= 3.14 (0.03232 m)^{2}= 1690.0736 ( mm)^{2}