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Part A, What is the magnitude of the electric force on charge A in the figure? F=______N
Part B, What is the direction of the electric force on charge A in the figure?
Choose best answer.
(a) to the left
(b) to the right
(c) the force is zero
♦ Relevant knowledgeThe force between two points charges is determined by Coulomb’s law. This force is proportional with the charge’s product and in reverse proportion to the square of distance between charges. The direction of force is towards the other charges when they are of the same type, or else, it attracts.
Part A,
Below is the diagram of the three-point charges.
The charge at point B creates the electric force at point A.
qA, qB represent the two points charges, and AB represents the distance between the charges.
Substitute 9 × 109 N. m2 / C2 to k; 1 m to AB; 1 nC to qA; 1 nC to qA ; 1 nC to qB
The charge at point C creates the electric force at point A.
qA, qC represent the two points charges, and represents the distance between the charges.
Substitute 9 × 109 N. m2 / C2 to k; 1 m to AB; 1 nC to qA; 1 nC and 4 nC
The net force that is acting on the charge at point A is
The magnitude the net electric force acting upon the charge at point A in 0 N .
Part B,
0 N is the net electric force that acts at charge A. Therefore, the force acting at the charge A is zero.
A diagram and Coulomb’s law of electrostatics are the concepts that were used to answer the question.
First, draw the diagram showing the two point charges. Next, use Coulomb’s law for electrostatics to determine the magnitude of the two points and the direction of the charges.
“Coulomb’s law says that the force between two point charges is proportional to their respective magnitudes and ininverse proportion to the distance between them.
It is mathematically defined as:
(A)
Below is the diagram of the three-point charges.
The charge at point B creates the electric force at point A.
Substitute
to
; 
to
; 
to 
; 
to 
; 
to 
The charge at point C creates the electric force at point A.
Substitute
to
; 
to
; 
to 
; 
and 
respectively for 
The net force that is acting on the charge at point B is
Substitute [katex]9×10^{-9}[/katex] to [katex]F_{AB}[/katex] or [katex]9×10^{-9}N[/katex] to
(B)
Accordingly, A is the charge for which the force acts. Part A – Ans
The magnitude the net electric force acting upon the charge at point A in
.