Home/ Questions/Part A: Write an equation for the formation of NO(g) from its elements in their standard...
Next
Answered
lyytutoria
  • 18
Expert
Asked: 2022-04-13T06:52:14+00:00 In:

Part A: Write an equation for the formation of NO(g) from its elements in their standard…

  • 18

. Advertisement .

..3..

. Advertisement .

..4..

......... ADVERTISEMENT .........

..8..

Part%20A:%20Write%20an%20equation%20for%20the%20formation%20of%20NO(g)%20from%20its%20elements%20in%20their%20standard...

Part A:

Write an equation for the formation of NO(g) from its elements in their standard states.

Express your answer as a chemical equation. Identify all of the phases in your answer.

Part B:

Write an equation for the formation of BF3(g) from its elements in their standard states.

Express your answer as a chemical equation. Identify all of the phases in your answer.

Part C:

Write an equation for the formation of C6H6(l) from its elements in their standard states.

Express your answer as a chemical equation. Identify all of the phases in your answer.

Part D:

Write an equation for the formation of HF(g) from its elements in their standard states.

Express your answer as a chemical equation. Identify all of the phases in your answer.

♦ Relevant knowledge

In ideal conditions of pressure and temperature the process of forming any substance is accompanied by a change in enthalpy that is known as the standard enthalpy of the formation. The standard enthalpy can be calculated for a specific reaction by looking at the difference between the established norms for the production of reactants and the products.

enthalpiesformationstandard
Share

1 Answer

  1. Best Answer

    Part A

    N2(g), the standard state of N, is

    O2(g), the standard state of O, is O2(g).

    The formation reaction is therefore:

    1/2 N2(g) + 1/2 O2(g) -> NO(g)

    Part B

    Standard state of B (s)

    F2(g), the standard state of F, is F2(g).

    The formation reaction is therefore:

    B(s) + 3/2 F2(g) -> BF3(g)

    Part C

    Standard state of C (s,graphite),

    Standard state for H is H2(g).

    The formation reaction is therefore:

    6 C(s,graphite) + 3 H2(g) -> C6H6(l)

    Part D

    H2(g), the standard state of H, is

    F2(g), the standard state of F, is F2(g).

    The formation reaction is therefore:

    1/2 H2(g) + 1/2 F2(g) -> HF(g)

    • 9

Leave an answer

You must login to add an answer.

Need An Account,