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Home/Questions/Is there any solution for the promise already under evaluation: recursive default argument reference or earlier problems?
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Delilah O'Brien
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Delilah O'Brien
Asked: May 18, 20222022-05-18T19:53:00+00:00 2022-05-18T19:53:00+00:00In: r

Is there any solution for the promise already under evaluation: recursive default argument reference or earlier problems?

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I encountered the following problem in completing my work:

> test()
  Error in test() :
  promise already under evaluation: recursive default argument reference or earlier problems?

Below is the code I ran:

f <- function(x, T) {
  10 * sin(0.3 * x) * sin(1.3 * x ^ 2) + 0.001 * x ^ 3 + 0.2 * x + 80
 }
 
 g <- function(x, T, f=f) {
  exp(-f(x) / T)
 }
 
 test <- function(g=g, T=1) { 
  g(1, T)
 }

What’s causing it, and how can it be resolved in the “promise already under evaluation: recursive default argument reference or earlier problems“ in the r?

recursive default argument reference or earlier problems
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    dttutoria Expert
    2022-06-25T02:45:08+00:00Added an answer on June 25, 2022 at 2:45 am

    The cause: This is caused by formal arguments of the type x=x. We obtain the following when we take out the two instances where they appear. (You can’t use x=x in the formal arguments of a function declaration because it first searches up the default parameter within the function; using that form would be instructing it to use itself as the default, but because it hasn’t been defined, it wouldn’t make sense, and we would receive an error.)

    Solution: Try this code to fix the promise already under evaluation: recursive default argument reference or earlier problems:

    f <- function(x, T) {
    10 * sin(0.3 * x) * sin(1.3 * x^2) + 0.001 * x^3 + 0.2 * x + 80
    }
    
    g <- function(x, T, f. = f) { ## 1. note f.
    exp(-f.(x)/T)
    }
    
    test<- function(g. = g, T = 1) { ## 2. note g.
    g.(1,T)
    }
    
    test()
    ## [1] 8.560335e-37
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  2. Léna Robin
    2022-05-25T20:58:38+00:00Added an answer on May 25, 2022 at 8:58 pm

    You can avoid the problem of the same name by especifying argument evaluation context

    f <- function(x) {
     10 * sin(0.3 * x) * sin(1.3 * x ^ 2) + 0.001 * x ^ 3 + 0.2 * x + 80
    }
    g <- function(x, t=1, f=parent.frame()$f) {
     exp(-f(x) / t)
    }
    test <- function(g=parent.frame()$g, t=1) { 
     g(1,t)
    }
    test()
    [1] 8.560335e-37
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