Home/ Questions/Is there any solution for the promise already under evaluation: recursive default argument reference or earlier problems?
Next
Answered
Delilah O'Brien
  • 24
Asked: 2022-05-18T19:53:00+00:00 In:

Is there any solution for the promise already under evaluation: recursive default argument reference or earlier problems?

  • 24

. Advertisement .

..3..

. Advertisement .

..4..

I encountered the following problem in completing my work:

> test()
  Error in test() :
  promise already under evaluation: recursive default argument reference or earlier problems?

Below is the code I ran:

f <- function(x, T) {
  10 * sin(0.3 * x) * sin(1.3 * x ^ 2) + 0.001 * x ^ 3 + 0.2 * x + 80
 }
 
 g <- function(x, T, f=f) {
  exp(-f(x) / T)
 }
 
 test <- function(g=g, T=1) { 
  g(1, T)
 }

What’s causing it, and how can it be resolved in the “promise already under evaluation: recursive default argument reference or earlier problems“ in the r?

recursive default argument reference or earlier problems
Share

2 Answers

  1. Best Answer
    Expert

    The cause: This is caused by formal arguments of the type x=x. We obtain the following when we take out the two instances where they appear. (You can’t use x=x in the formal arguments of a function declaration because it first searches up the default parameter within the function; using that form would be instructing it to use itself as the default, but because it hasn’t been defined, it wouldn’t make sense, and we would receive an error.)

    Solution: Try this code to fix the promise already under evaluation: recursive default argument reference or earlier problems:

    f <- function(x, T) {
10 * sin(0.3 * x) * sin(1.3 * x^2) + 0.001 * x^3 + 0.2 * x + 80
}

g <- function(x, T, f. = f) { ## 1. note f.
exp(-f.(x)/T)
}

test<- function(g. = g, T = 1) { ## 2. note g.
g.(1,T)
}

test()
## [1] 8.560335e-37
    • 0

  2. You can avoid the problem of the same name by especifying argument evaluation context 

    f <- function(x) {
 10 * sin(0.3 * x) * sin(1.3 * x ^ 2) + 0.001 * x ^ 3 + 0.2 * x + 80
}
g <- function(x, t=1, f=parent.frame()$f) {
 exp(-f(x) / t)
}
test <- function(g=parent.frame()$g, t=1) { 
 g(1,t)
}
test()
[1] 8.560335e-37
    • 13

Leave an answer

You must login to add an answer.

Need An Account,