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Home/ Questions/Provide a structure for the following compound: C6H12O2: IR: 1743 cm-1; 1H NMR spectrum:
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lyytutoria
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lyytutoriaExpert
Asked: April 13, 20222022-04-13T08:16:40+00:00 2022-04-13T08:16:40+00:00In: Chemistry

Provide a structure for the following compound: C6H12O2: IR: 1743 cm-1; 1H NMR spectrum:

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Provide%20a%20structure%20for%20the%20following%20compound:%20C6H12O2:%20IR:%201743%20cm-1;%201H%20NMR%20spectrum:

Provide a structure for the following compound:
C6H12O2:
IR: 1743 cm-1;
1H NMR spectrum:
                                                           chemical shift, Hz

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                                                            chemical shift, ppm (δ)
♦ Relevant knowledge

Nuclear magnetic resonance, also known as NMR also known as spectroscopy, is a spectroscopic method that is built on the magnetic properties of nuclear nuclei. This technique is used to study the structure of organic compounds in particular 1H NMR as well as 13C NMR spectroscopy.

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    John Li
    2022-04-13T08:21:42+00:00Added an answer on April 13, 2022 at 8:21 am
    Concepts and Reason

    1H NMR Spectroscopy:

    It’s used to identify organic compound structures. This tool uses an external magnetic field to determine the different types of hydrogens present in a molecule.

    Infrared Spectroscopy:

    Infrared spectroscopy can be used to identify the functional groups within chemical compounds. This is also known as vibrational spectroscopy. A compound with covalent bonds absorbs electromagnetic radiation at a variety of frequencies in the infrared area of the electromagnetic spectrum. IR radiations are found in the wavelength range 400 – 800 nm.

    Fundamentals

    1HNMR Spin-Spin Coupling Designs:

    Number of neighboring
hydrogens (chemically non-
equivalent)
n
0
Number of
peaks
(n+1)
Splitting
Name
Peak
heights
ratio
2
Si

    The degree of unsaturation

    1_2C+N-H-X+2
where,
Degree of unsaturation is DoU.
The number of carbons is C.
The number of nitrogen is N.
The number of hyd

    The mathematical equation that calculates the IR wavenumber

    1
2Nc

    Where,

    Wavenumber absorption =

    Velocity of light =

    Force constant =

    Reduced mass =

    Frequency and range of absorption in IR:

    absorption
Functional group
Range of
(cm)
2800-2900
3400-3600
1640-1680
3020-3100
2100-2250
3300
2200-2250
Alkane(C-H)
Alcoho

    Given molecular formula:
C,H,O,
DoU = 2x6+0-12-0+2
Dou = 12–12+2
DoU = ?
DoU = 1 (It has one double bond)

    Molecular Formula =C,H,O,
IR Frequency = 1743 cm
Ester Functional Group, RCOOR=1750-1735 cm

    Numbe
2H
From the given H NMR spectra :
Chemical shift
Around 4 ppm (most deshielded)
Around 2.3 ppm
Around 1.6 ppm
Around 1

     

    The correct structure is for most deshielded hydrocarbons with triplet.

    H3C—CH2—6—0-
CH2-CH2-CH3

    Mention multiplicity and number of hydrogens:
2H, 2.3 ppm o
2H, 1.6 ppm
H3c7ichz—0–CH2CH2 CH3
3H, 1.1 ppm
2H, 4.0 ppm
3H, 0.9 Ans:

    The structure of the organic compound given is

    H3C-CH2-6-0-
CH2-CH2-CH3

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