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_{1}=

**Ω, R**

*19*_{2}=

**Ω, R**

*75*_{3}=

**Ω, R**

*89*_{4}=

**Ω, and R**

*64*_{5}=

**Ω, and the emf of the battery is e =**

*26***V. Suppose the internal resistance of the battery is zero.**

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**Part (a)**Express the equivalent resistance of the combination of

*R*and

_{2}, R_{3},*R*.

_{4 }

*R*_{eq}=......... ADVERTISEMENT .........

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**Part (b)**Express the total resistance of the circuit

*R*in terms of

*R*and

_{1}, R_{2}, R_{3}, R_{4},*R*.

_{5}**Part (c)**Calculate the numerical value of the total resistance

*R*in

*Ω*.

**Part (d)**Express the current

*I*through

*R*, in terms of the emf

_{1}*ε*and the equivalent resistance

*R*.

**Part (e)**Calculate the numerical value of

*I*in

*A*.

**Part (f)**Express the power

*P*dissipated by

*R*, through

_{1}*I*and

*R*.

_{I}**Part (g)**Calculate the numerical value of the power

*P*in

*W*.

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Imagine a circuit comprised of many resistors that form an intricate arrangement. It is difficult to estimate the voltage drop and current that flows through each resistor, but it is possible to use the same resistors to make the circuit simpler. Think about replacing the complete set of resistors by just one resistor, which produces exactly the same drop in voltage as well as the same current as in the initial collection. Its resistance hypothetical resistor is that of the arrangement’s the resistance of ** R_{eq}**.

## 1 Answer