Home/ Questions/The easy way to handle error - reference to non-static member function must be called
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Nyla Smith
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Asked: 2022-05-18T17:33:33+00:00 In:

The easy way to handle error – reference to non-static member function must be called

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How to solve the problem – reference to non-static member function must be called? I have the sample detail:

void MyClass::buttonClickedEvent( int buttonId ) {
  // I need to have an access to all members of MyClass's class
 }
 
 void MyClass::setEvent() {
 
  void ( *func ) ( int ); 
  func = buttonClickedEvent; // <-- Reference to non static member function must be called
 
 }
 
 setEvent();

While I was running it, I found the warning message:

Reference to non static member function must be called

That is my question in my midterm exam, and it is urgent. I searched the solutions for some websites, but I didn’t get it. I may miss any line or other changes. I appreciate your assistance!

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2 Answers

  1. Best Answer
    Expert

    The cause: The issue is that buttonClickedEvent is a member function, and calling it requires a pointer to a member.

    Solution: 

    Do this:

    void (MyClass::*func)(int);
func = &MyClass::buttonClickedEvent;

    Then, in order to use it, you must have an object of type MyClass, such as this:

    (this->*func)(<argument>);

     

    • 0

  2. You may want to have a look at https://isocpp.org/wiki/faq/pointers-to-members#fnptr-vs-memfnptr-types, especially [33.1] Is the type of “pointer-to-member-function” different from “pointer-to-function”?

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