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m = given mass = 110 mg = 0.110 g
M = molar mass = 4 g/mol
N = Number of Moles
n = M/M = 0.110/4 =0.0275
Part A
Point 1:
T 1 = Temperature At Point 1 = 133C = 133 + 273 = 406 K
V 1 = Volume At Point 1 = 1000 cm = 10 -3 M
P 1 = Pressure at Point 1 =?
Use the equation
P1 V1 = n R
T1
Inserting the values
P1 (10-3 ) = (0.0275) (8.314) (406)
P1= 92825.8 p = 0.916
atm
Point 2:
P2= 5 P1 = 5 (0.916) = 4.58 atm
Point 3:
P3 = P1 = 0.916
atm
Part B)
T1 = 133 oC
Process 1 and 2:
P1/T1 =
P2/T2 (Since volume is constant)
P1/(133 + 273) = 5P1/T2
T 2 = 2030K
T2= 2030 – 273 = 1757
oC
T3 = T2 = 1757
oC
Part C
V1 = 1000 cm3
V2= V1 = 1000
cm3
V1/T1 = V3 /T3
1000/(133 + 273) = V3 /2030
V3 = 5000 cm3
Part D
for process 1-2 :
V = 0
W1-2= P1V = 0
for process 2-3 :
W 2-3 = N R T 2 log (V 3/V 2).
W2-3= (0.0275) (8.314) (2030) log(5000/1000) = 747 J
for process 3-1:
W3-1= P1 (V1 – V3) = (92825.8) (0.001 – 0.005) = – 371.3
J