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Home/ Questions/The figure(Figure 1) shows a thermodynamic process followed by 110 ng of helium....
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lyytutoria
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lyytutoriaExpert
Asked: April 13, 20222022-04-13T07:00:16+00:00 2022-04-13T07:00:16+00:00In: Physics

The figure(Figure 1) shows a thermodynamic process followed by 110 ng of helium….

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The figure(Figure 1) shows a thermodynamic process followed by 110 ng of helium. You may want to review (Page 515)
For help with math skills, you may want to review:
Conversion Factors
Conversion Between Celsius and Kelvin
Rearrangement of Equations Involving Multiplication and
Figure

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Part A Determine the pressure (in atm) of the gas at points 1, 2, and 3
p1,p2,p3 = 0.999,5.0,0.999 atm 
Part B Determine the temperature (in °C) of the gas at points 1, 2, and 3 
T1,T2,T3 =                              °C
Part C Determine the volume (in cm3) of the gas at points 1, 2, and 3.
V1,V2,V3 =                             cm3
Part D How much work is done on the gas during each of the three 
W1→2,W2→3,W3→1 =            J
Part E How much heat energy is transferred to or from the gas during each of the three segments? 
Q1→2,Q2→3,Q3→1 =               J

♦ Relevant knowledge

The first law of thermodynamics states that any change to inner energy that the system produces is proportional to the amount of heat transferred or added plus the work that is done in the course of the system.
                                                              ΔU=Q−W
The S.I unit of energy is Joules (J).
pressuretemperature
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    lyytutoria Expert
    2022-05-02T08:22:59+00:00Added an answer on May 2, 2022 at 8:22 am

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  2. Joanne O'Connor
    2022-04-13T07:21:04+00:00Added an answer on April 13, 2022 at 7:21 am

    m = given mass = 110 mg = 0.110 g

    M = molar mass = 4 g/mol

    N = Number of Moles

    n = M/M = 0.110/4 =0.0275

    Part A

    Point 1:

    T 1 = Temperature At Point 1 = 133C = 133 + 273 = 406 K

    V 1 = Volume At Point 1 = 1000 cm = 10 -3 M

    P 1 = Pressure at Point 1 =?

    Use the equation

    P1 V1 = n R
    T1

    Inserting the values

    P1 (10-3 ) = (0.0275) (8.314) (406)

    P1= 92825.8 p = 0.916
    atm

    Point 2:

    P2= 5 P1 = 5 (0.916) = 4.58 atm

    Point 3:

    P3 = P1 = 0.916
    atm

    Part B)

    T1 = 133 oC

    Process 1 and 2:

    P1/T1 =
    P2/T2   
    (Since volume is constant)

    P1/(133 + 273) = 5P1/T2

    T 2 = 2030K

    T2= 2030 – 273 = 1757
    oC

    T3 = T2 = 1757
    oC       

    Part C

    V1 = 1000 cm3

    V2= V1 = 1000
    cm3

    V1/T1 = V3 /T3

    1000/(133 + 273) = V3 /2030

    V3 = 5000 cm3

    Part D

    for process 1-2 :

    Review%20Part%20A%20The%20figure(Figure%201)%20shows%20a%20thermodynamic%20process%20followed%20by%20110%20ng%20of%20helium....V = 0

    W1-2= P1Review%20Part%20A%20The%20figure(Figure%201)%20shows%20a%20thermodynamic%20process%20followed%20by%20110%20ng%20of%20helium....V = 0

    for process 2-3 :

    W 2-3 = N R T 2 log (V 3/V 2).

    W2-3= (0.0275) (8.314) (2030) log(5000/1000) = 747 J

    for process 3-1:

    W3-1= P1 (V1 – V3) = (92825.8) (0.001 – 0.005) = – 371.3
    J

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