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Louise Barbe
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Asked: 2022-05-11T18:45:40+00:00 In:

Fixing the error: runtimewarning: invalid value encountered in true_divide

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This is the program I run:

from pylab import*
 from math import*
 m=0.1
 Lo=1
 tt=30
 k=200
 t=20
 g=9.81
 dt=0.01
 n=int((ceil(t/dt)))
 km=k/m
 r0=[-5,5*sqrt(3)]
 v0=[-5,5*sqrt(3)]
 a=zeros((n,2))
 r=zeros((n,2))
 v=zeros((n,2))
 t=zeros((n,2))
 r[1,:]=r0
 v[1,:]=v0
 for i in range(n-1):
  rr=dot(r[i,:],r[i,:])**0.5
  a=-g+km*cos(tt)*(rr-L0)*r[i,:]/rr
  v[i+1,:]=v[i,:]+a*dt
  r[i+1,:]=r[i,:]+v[i+1,:]*dt
  t[i+1]=t[i]+dt
 
  #print norm(r[i,:])
 
 plot(r[:,0],r[:,1])
 xlim(-100,100)
 ylim(-100,100)
 xlabel('x [m]')
 ylabel('y [m]')
 
 show()

After I run, it returns an error

a=-g+km*cos(tt)*(rr-L0)*r[i,:]/rr
 RuntimeWarning: invalid value encountered in divide

Does anyone have any suggestions for my problem: runtimewarning: invalid value encountered in true_divide in the programs. How to correct it?

python-2.7
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3 Answers

  1. Best Answer

    I have some recommendation for your problem

    Array2 = np.array([3, 2, 0])
# Supress/hide the warning
np.seterr(invalid='ignore')
# divide the values in Array1 by the
# values in Array2
np.divide(Array1, Array2)

    The output is:

    array([ 2., 1., nan])
    • 21

  2. Divide rr, which could be 0.0. You can check rr to see if it is zero.

    • 6

  3. Your code may be trying to “divide zero” or “divide NaN”. You can do this if you’re aware of it and don’t mind it.

    import numpy as np
np.seterr(divide='ignore', invalid='ignore')
    • 0

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