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Home/ Questions/The static error: ''this class does not have a static void main method accepting string[]'' error. What should you do?
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Elina Johnson
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Elina Johnson
Asked: May 18, 20222022-05-18T20:01:26+00:00 2022-05-18T20:01:26+00:00In: java

The static error: ”this class does not have a static void main method accepting string[]” error. What should you do?

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I get the error: static error: this class does not have a static void main method accepting string[]. When I try to run the program below:

/**
  * @author "LionH"
  */
 public class Caneirinho {
 
  public static void contar() {
  int i = 1;
  String a = " Carneirinho",
  b = " pulando a cerca.",
  c = "s";
 
  for (i = 1; i <= 100; i++) {
  if (i == 1) {
  System.out.println(i + a + b);
  } else { 
  System.out.println(i + a + c + b);
  }
  }
  }
 } // Carneirinho

The error appears the system notifies as follows:

Static Error: This class does not have a static void main method accepting String[].

I tried to solve it with another sample. I got the reference in the community forum, but it still returned an invalid result. If someone knows the solution, please give me the support. Thanks!

static error
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    lyytutoria Expert
    2022-06-23T13:37:51+00:00Added an answer on June 23, 2022 at 1:37 pm

    The cause:

    After looking over your problem, I found that you had some classes in your Java program, but you didn’t create a main class to do the classes which you had specified. That’s the reason why you had got this error.

    Solution:

    To solve this error, you need to replace contar() to main(String args[]). 

    Look at below:

    public class Caneirinho{
    
    public static void contar(){
    int i = 1;
    String a = " Carneirinho",
    b = " pulando a cerca.",
    c = "s";
    
    for(i=1; i<=100; i++){
    if(i==1){
    System.out.println( i + a + b );
    } else {
    System.out.println( i + a + c + b );
    Thread.sleep(1000); // thread wais for 1 sec ie 1000 milisecond
    }
    }
    }
    
    public static void main(String[] args){
    contar(); // call contar() from main method
    }
    
    }//Carneirinho

    If you do as my above suggestions, the error will not exist and your program will work well. Good lucks!!!

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  2. Mia Poisson
    2022-05-25T21:00:19+00:00Added an answer on May 25, 2022 at 9:00 pm

    A main method must be present in any Java class you are running directly. This is the entry point. It tells you where the program begins when you execute the code.

    public static void main(String args[])

    It should work by changing the contar() name to main(String args[])

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